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Thread: unreported exception

  1. #1
    Junior Member
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    Default unreported exception

    Why doesn't my code compile?

    Here's the code:
    public class Exceptions
    {
    	public void method1(int x)
    	{	
    		if (x < 0)
    			throw new Exception("ERROR: Negative value in X coordinate.");
    	}
     
    	public static void main(String[] args)
    	{	Exceptions ex = new Exceptions();
    		try
    		{	ex.method1(-1);
    		}
    		catch (Exception e)
    		{	System.out.print(e.getMessage());
    			e.printStackTrace();
    		}
    	}
    }

    Error message:
    Exceptions.java:6: error: unreported exception Exception; must be caught or declared to be thrown
    throw new Exception("ERROR: Negative value in X coordinate.");
    ^
    1 error
    Last edited by Bao; August 5th, 2019 at 08:35 AM. Reason: Problem solved

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: unreported exception

    Exceptions.java:6: error: unreported exception Exception; must be caught or declared to be thrown
    method1 must either:
    declare that it throws the exception by having a throws clause in its definition
    or it must use a try{}catch block to catch and handle the exception
    If you don't understand my answer, don't ignore it, ask a question.

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