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Thread: Try/Catch exception so i can return an array and print out an exception too

  1. #1
    Junior Member
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    Mar 2012
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    Default Try/Catch exception so i can return an array and print out an exception too

    Hi i am writing a lottery method where the user has to enter in two numbers, n and k, as arguments. The lottery gets filled with a randomized queue that goes up to k. so if i put in k=10 the queue would hold 1,2,3,4,5,6,7,8,9,10. The argument n is the number of items that has to be removed randomly. so if i chose 3 then it could return 4,6,8 or it could be 1,3,10.

    Now if n is greater than k it has to throw an error saying that there is not enough items in the queue to pull. So if i put n=5 and k=3, there are still 3 items in the queue but i can't select 5.

    Now my problem is i have to return the items that are still in the queue. so n=5 and k=3 would return 1,3,2 or 2,3,1 and so forth. But i have to print an exception after i return that array. So far i am able to return the array but i can not get the try catch exception to work. Is there another method i can try that will return the array and then print out the exception after that so it looks like this:

    %java Lottery 5 2
    2  1
    java.lang.Exception: Not enough items in your queue.
    at Lottery.pickNumbers(Lottery.java:29)
    at Lottery.main(Lottery.java:56)

    Here is my code

    import java.util.*;
    import java.math.*;
    public class Lottery{
        RandomizedQueue rq;
        Random Rnum = new Random();
        int [] Larray;
        // constructs a Lottery class
        public Lottery(){
        // picks the numbers and store them in an array of integers
        // int n: number of items to pick
        // int k: maximum integer to be picked
        public int [] pickNumbers(int n, int k) throws Exception{
        	rq = new RandomizedQueue();
        	int [] remainQueue = new int [k];
        		for(int i=1; i<=remainQueue.length;i++)
    	    		for(int i =0; i<remainQueue.length;i++)
    	    			remainQueue[i] = rq.dequeue();
    	    			catch (Exception e)
    	    				System.out.println("not enough items in the queue");
    	    		return remainQueue;	
        	for(int i =1;i<=k;i++)
        	Larray = new int[n];
        	for(int i = 0;i< Larray.length;i++)
        		Larray[i] = rq.dequeue();
        	return Larray;
        // Do not change main().
        public static void main(String [] args) throws Exception{
        	if (args.length<2){
    	       System.out.println("Please enter your input values.");
    	       System.out.println("e.g. java Lottery [number of integers to pick] [Maximum integer to be picked]");
    	       int n = Integer.parseInt(args[0]);
    	       int k = Integer.parseInt(args[1]);
    	       Lottery l = new Lottery();
    		   int [] picked = l.pickNumbers(n,k);
    		   for (int i = 0; i< picked.length; i++){
    		       System.out.print(picked[i]+" ");
    	       }catch (Exception e){

  2. #2
    Crazy Cat Lady KevinWorkman's Avatar
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    Default Re: Try/Catch exception so i can return an array and print out an exception too

    You might want to check out the finally block.
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