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Thread: ZipEntry to InputStream or java.io.File. How?

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    Question ZipEntry to InputStream or java.io.File. How?

    Hi,
    I've spent many hours trying to find a solution to this problem, but all in vain.
    Here's the deal:
    I have a ZipInputStream, which I've even managed to get a ZipEntry from.
    I can get the size or the name of this entry. The entry itself is an XML file which I need to get access to,
    but how can I do that without a ZipFile instance?

    Here's my code so far:
    ByteArrayInputStream    bais           = new ByteArrayInputStream(zipBytes);     
     ZipInputStream            zis            = new ZipInputStream(bais);
    ZipEntry                      ze             = zis.getNextEntry();
    I need to extract the entry as InputStream or java.io.File to pass it to a DocumentBuilder and parse the XML.
    Any ideas?

    thanks.


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    Default Re: ZipEntry to InputStream or java.io.File. How?

    After you get the ZipEntry have you tried reading from the ZipInputStream to read its data?
    Read the API doc for the getNextEntry() method.

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    Default Re: ZipEntry to InputStream or java.io.File. How?

    Yeah, I did it..
    I seem to have found the problem, it's my overtiredness. I forgot the XML file is XOR encrypted, that's why it can't read it

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    Default Re: ZipEntry to InputStream or java.io.File. How?

    Well, I was wrong, the encryption was not a problem.
    I cannot even get the size of the entry. It always returns -1.
    I've managed to google out that it's because the size is written after the entry.
    Like I can easily get it from ZipFile, but the problem is that I don't have a zip file, I only have a ZipInputStream..
    It there any workaround to it?
    Last edited by goodguy; November 27th, 2011 at 03:21 AM.

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    Default Re: ZipEntry to InputStream or java.io.File. How?

    For testing try creating a zip file in a byte array and then getting a ZipInputStream on that and reading from it. Then post the code here if you can't get it to work.

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