Thread: Java 2d Character array

for(int i=0;i<c1+1;i++)
{
for(int j=0;j<3;j++)
{
System.out.print(ascii[i][j]);

}
// System.out.println();
}

System.out.println();

int digit[] = new int[c.length];


for(int i=0;i<c1+1;i++)
{
for(int j=0;j<ascii[i].length;j++)
{

digit[i] = Integer.parseInt(String.valueOf(ascii[i][j]));
}
}

for(int i=0;i<digit.length;i++)
{
System.out.print(digit[i]);

}


My question is that
1. First I want to convert 2d character array contain number into 2d intger array. for eg. "8" -> 8
2. Then want to make row of each 2d int array into string. 8 5 -> "85"
3. Then convert string into character array. "85" -> U

Problem with my code:
1. Not able to convert the 2d character array into the 2d integer array.

convert 2d character array contain number and into 2d intger array.

Can you explain what the conversion would do to a char to make an int? For example: 'A' > 1, 'B' > 2, etc

make row of each 2d int array into string

What would that conversion look like? For example: {123, 345} > "123345"

convert it into character array.

What is the "it"? The String class has a method to convert a String

Please edit your post and wrap your code with code tags:

[code]
**YOUR CODE GOES HERE**
[/code]

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"8" -> 8

Look at the Integer class. It has a method to convert a String to an int

make row of each 2d int array into string. 8 5 -> "85"

Look at the Integer class for a method to convert an int to a String then use the String concatenation operator + to concatenate the Strings into a single String

convert string into character array. "85" -> U

Use the Integer class to convert the String into a int and then cast the int to a char: (char)85 is 'U'

it doesnt work

Please explain. Post the code wrapped in code tags and any error messages you get.
Also post any print outs that show what the code does.