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Thread: Modulo operation

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    Default Modulo operation

    Hello! I am not quite sure about the output of this program,meaning my calculation and the programs are diffrent.

    public class test2 {
    	public static void main(String[] args) {
    		char c = 'd';
     
    	Out.println(++c % c--);
    	}
    }

    Now the value of 'd' in the ASCII table is 100 so what I think is happening in the program(the print stament) is the value of d is increased by one and than % with 100.So it should be 101%100 which should print out 1.But the program prints out 0 suggestion it was 100%100.What am I missing here? I know the first one is a preincrement meaning the value of c will be increased but does the modulo operation have precedence or? Some clearification would be great, thanks!

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    Super Moderator Norm's Avatar
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    Default Re: Modulo operation

    Why write such tricky code? Simplify it so it is easy to understand and debug.
    No one writes code like that.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Modulo operation

    It is an task from a test ,you are given such complicated and tricky codes and you have to guess what the print out will be, that is why.

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    Default Re: Modulo operation

    Ok, when that expression is executed:
    what is the value to the left of the %
    what is the value to the right of the %
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Modulo operation

    Well, If you would to ask me I would say 101 left, 100 right. Left we have preincrement, and right we have post increment.

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    Default Re: Modulo operation

    Read up on the post increment. What value does it return when used in an expression? When is the value incremented?
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Modulo operation

    Yea i've figured it out.After the ++c the value of i becomes 101, making the value of i in i-- also 101 thus 101%101 = 0; The i--; will take place after this expression.

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    Default Re: Modulo operation

    Yes, that sounds right.
    If you don't understand my answer, don't ignore it, ask a question.

  9. The Following User Says Thank You to Norm For This Useful Post:

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