Thread: Boolean code question!

Hello!

My question that I'm creating a code for is as follows:

Write the following methods and provide a program to test them:
boolean sorted(double x, double y, double z),returning true if the arguments are sorted, with the smallest one coming first.

This is my code:

import java.util.Scanner;
public class a3q1
{
        public static void main ( String args[])
   {
Scanner in = new Scanner(System.in);
 
double x = in.nextDouble();
double y = in.nextDouble();
double z = in.nextDouble();
   }
public static boolean inorder(double x, double y, double z) {
if (x < y && y < z) {
System.out.println("Correct!");
}
 
else {
System.out.println("incorrect. Try again!");
   }
}
}

For some reason however, it won't compile. My question is, how do I fix the compiling error, and do you think this code is suitable for the question asked?

Originally Posted by KevinWorkman

What is the compiler error?

By the way, you flubbed up your code tags.

Heh, yeah. Fixed that.

The compiler error is:


a3q1.java:20: missing return statement
}
^
1 error

This code compiles with no syntax errors. This program calls your inorder() method and returns true or false in the main method.

import java.util.Scanner;
 
public class a3q1
{
public static void main ( String args[])
   {
       Scanner in = new Scanner(System.in);
 
       double x = in.nextDouble();
       double y = in.nextDouble();
       double z = in.nextDouble();
       boolean myb = inorder( x, y, z );    //call method inorder() and pass variables x, y, and z to the argument. Return value is stored in boolean
 
       if( myb = true )
            System.out.println("Correct!");
       else
            System.out.println("incorrect. Try again!");
 
}//end of main method
 
public static boolean inorder(double x, double y, double z) {
    if (x < y && y < z) 
        return true;
    else 
        return false;
 
    }//end of inorder method
}//end of cloass

Originally Posted by KevinWorkman

Zyrion, please read this: http://www.javaprogrammingforums.com...n-feeding.html

I understand.