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Thread: Given an array of numbers from 1 to 100 with exactly k numbers missing, find the missing numbers.

  1. #1
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    Default Given an array of numbers from 1 to 100 with exactly k numbers missing, find the missing numbers.

    I recently had an interesting job interview where the first question was quite straightforward.
    Q1: We have a bag containing numbers 1, 2, 3, , 100. Each number appears exactly once, so there are 100 numbers. Now one number is randomly picked out of the bag. Find the missing number.

    I was well prepared for this question as I had heard it before, so I was able to quickly respond with an answer that was relevant to the question.

    A1: Well, the sum of the numbers 1 + 2 + 3 + + N is (N+1)(N/2) (see: https://www.interviewbit.com/problem...c-progression/). For N = 100, the sum is 5050.

    Thus, if all numbers are present in the bag, the sum will be exactly 5050. Since one number is missing, the sum will be less than this, and the difference is that number. So we can find that missing number in O(N) time and O(1) space.

    I was feeling confident about my performance up to that point, but then the question abruptly changed direction.
    Q2: That is correct, but now how would you do this if TWO numbers are missing?

    I had never seen/heard/considered this variation before, so I panicked and couldn't answer the question. The interviewer insisted on knowing my thought process, so I mentioned that perhaps we can get more information by comparing against the expected product, or perhaps doing a second pass after having gathered some information from the first pass, etc. Still, I really was shooting in the dark rather than actually having a clear path to the solution.

    The interviewer did try to encourage me by saying that having a second equation is indeed one way to solve the problem. At this point, I was kind of upset (for not knowing the answer beforehand), and asked if this was a general (read: "useful") programming technique, or if it was just a trick/gotcha answer.

    The interviewer's answer surprised me: you can generalize the technique to find 3 missing numbers. In fact, you can generalize it to find k missing numbers.

    Qk: If exactly k numbers are missing from the bag, how would you find it efficiently?

    This was a few months ago, and I still couldn't figure out what this technique is. Obviously, there's a Ω(N) time lower bound since we must scan all the numbers at least once, but the interviewer insisted that the TIME and SPACE complexity of the solving technique (minus the O(N) time input scan) is defined in k, not N.

    So the question here is simple:

    How would you solve Q2?
    How would you solve Q3?
    How would you solve Qk?


    Generally, there are N numbers from 1..N, not just 1..100.
    I'm not looking for the obvious set-based solution, e.g. using a bit set, encoding the presence/absence of each number by the value of a designated bit, therefore using O(N) bits in additional space. We can't afford any additional space proportional to N.
    I'm also not looking for the obvious sort-first approach. This and the set-based approach are worth mentioning in an interview (they are easy to implement, and depending on N, can be very practical). I'm looking for the Holy Grail solution (which may or may not be practical to implement but has the desired asymptotic characteristics nevertheless).
    So again, of course, you must scan the input in O(N), but you can only capture a small amount of information (defined in terms of k, not N), and must then find the k missing numbers somehow.

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    Default Re: Given an array of numbers from 1 to 100 with exactly k numbers missing, find the missing numbers.

    Here is a sample code in C++ to find the missing numbers in an array:

    #include <bits/stdc++.h>
    using namespace std;

    void missingNumbers(int arr[], int n, int k)
    // Create an array to store the frequency of numbers
    int freq[101] = { 0 };

    // Increment the frequency of the numbers in the array
    for (int i = 0; i < n; i++)

    // Print the missing numbers
    for (int i = 1; i <= 100; i++)
    if (freq[i] == 0)
    cout << i << " ";

    int main()
    int arr[] = {1, 2, 3, 4, 6, 7, 8, 9, 10};
    int n = sizeof(arr) / sizeof(arr[0]);
    int k = 100 - n;

    cout << "The missing numbers are: ";
    missingNumbers(arr, n, k);

    return 0;

    The output will be:

    The missing numbers are: 5

  3. #3
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    Default Re: Given an array of numbers from 1 to 100 with exactly k numbers missing, find the missing numbers.

    Well if we are talking about programming, then I would use a set.
    Load the content of the bag into a set, try to take out all the numbers from 1 to 100, if the operation fails the number is not in the set.

    If we have to stay on pure mathematical plain I am just as lost as you

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    Default Re: Given an array of numbers from 1 to 100 with exactly k numbers missing, find the missing numbers.

    Is there a way to judge the infinite set of numbers? K to 100 for example. Finding then the missing numbers. This could lead to an infinite amount of sets, but since it's finite, still an infinite amount of combinations with it. How would one start this off.

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