oriordc2
Junior Member

Hi, i am new to java and need help with the below program.


Write a program that reads integers, finds the smallest of them and counts its occurrences. Assume that the input ends with number 0. Suppose that you entered 6 2 5 2 2 3 0; the program finds that the smallest is 2 and the occurrence count for 2 is 3.
Hint: maintain two variables min and count. Min stores the current min number and count stores its occurrences. Initially assign the first number to min and 1 to count. Compare each subsequent number with min. If the number is less than min, assign it to min and reset count to 1. If the number is equal to min increment count to 1.

So far:

import java.util.Scanner;

public class MinOccur {

/** Main method */
public static void main(String[] args) {

// Create a Scanner
Scanner input = new Scanner(System.in);

int times = 1;

int count = 1;

int min; // The smallest of the integers entered


int minNumber = Integer.MAX_VALUE; //Setting up the Max Value as the Minimum Number (so that anything smaller is automatically placed as minNumber)


// Read an initial data
System.out.print(
"Enter an int value (the program exits if the input is 0): ");
int data = input.nextInt();
int minimum = data;

// Keep reading data until the input is 0
int sum = 0;
while (data != 0) {
sum += data;

// Read the next data
System.out.print(
"Enter an int value (the program exits if the input is 0): ");
data = input.nextInt();
}


if (data < minNumber) //checking number against MAX_VALUE, this causes the number imputted to automatically become the new minNumber
{
minNumber = data;
}


System.out.printf( "Smallest Number is %d\n", minNumber );

for (int i = 0; i < 100; i++)
count++;
count++;
if (minNumber > 1){times++;}

System.out.println("Number " + minNumber + " occurs " + times + " Times ");


}
}