Thread: Removing duplicates from an Array

I've been trying to figure this out.

package eliminatingduplicates;
 
import java.io.IOException;
import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;
 
/**
 * Name: Bilal Hasan
 * Course: CS 1337
 * Section: 501
 * Date:
 * IDE: NetBeans 7.0.1
 * Operating System: Ubuntu 11.10
 */
 
/*
 *
 * Description: To eliminate duplicates in an array
 */
public class EliminatingDuplicates {
 
    public static void main(String[] args) throws IOException
    {
        Scanner keyboard = new Scanner (System.in);
        Random rand = new Random ();
 
        int []array = {1,2,3,4,4,3,2,2,3,4};
                //new int [10];
 
        /*for (int i = 0; i < array.length; i++) {
            System.out.print("Enter integer " + (i+1) + ": ");
            array[i] = keyboard.nextInt();
 
        }*/
 
        Arrays.sort(array);
 
        int []duplicateNumbers = eliminateDuplicates(array);
        int[]count = new int[10];
 
        for (int i=0; i < duplicateNumbers.length-1; i++) {
 
            for (int j = i+1; j < duplicateNumbers.length; j++) {
 
            if (duplicateNumbers[i] == duplicateNumbers[j] && duplicateNumbers[i] != 0 && j != i)
            {
                System.out.println("Duplicate numbers are: " + duplicateNumbers[i]);
            }
 
            }  
        }
 
 
    }
 
    //////////////////////////////////////////////////////
 
    public static int[] eliminateDuplicates(int []numbers)
    {
        int []duplicates = new int [10];
        int j = 0;
 
        for (int i = 0; i < numbers.length-1; i++) {
                for (int l = i+1; l < numbers.length; l++)
            {
                if (duplicates [i] == duplicates [l] && l != i)
                            {
                                duplicates[j] = numbers[i];
                                System.out.println(duplicates[j]);
                                j++;
 
                            }
            }
        }
 
     return duplicates;   
    }//end eliminate dupe method
}

I definitely need to be pointed in the right direction.