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Thread: Counting String in Specific Alphabet

  1. #1
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    Default Counting String in Specific Alphabet

    Consider strings over the alphabet Σ = {a, b}, and the function count(n) that returns the
    number of strings of length n containing more a’s than b’s. For example, for n = 3, there
    are four such strings, namely, [”aaa”, ”aab”, ”aba”, ”baa”], so the count is 4. Implement the
    function in Java using recursion (Assume that you are not allowed to use any formula for the
    count.)

    I appreciate any help with this assignment, I'm completely stuck. Here's where's my head is at:

    static int count(int n, int c) {
    int a = 0;
    int b = 0;

    }
    static int count() {
    int c = 0;
    return c;
    }

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Counting String in Specific Alphabet

    Can you compute all the Strings, including such as bbb and bba etc, and reject those that don't have more a's than b's?
    If you don't understand my answer, don't ignore it, ask a question.

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