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Thread: Array Search Method

  1. #1
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    Default Array Search Method

    Thanks for taking the time to look at this code. Basically instead of printing out the row that the searched surname is on it prints out line[i][2] i++. How Can i fix this. The Array Size is line[6][5]. And When i search the Furthest surname (line[0][5])
    it gives me an array out of bounds exception. Thanks you in advance for the help.
    public void searchSurname(String[][] line){
     
            boolean found = false;
            Scanner scan=new Scanner(System.in);
            String searchKey=scan.nextLine();
            int column = 0;
            for(int i=0; i<6; i++){
                    if(searchKey.equalsIgnoreCase(line[i][column])){
                            found = true;
                            column = i;
                    }
            }
            if(found==true){
                    System.out.println("Person is found!");
                    for(int i=0; i<line.length;i++){
                            System.out.println(line[i][column]);
                    }
            }else if(found==false){
                    System.out.println("Person is not found");
            }


  2. #2
    Member OutputStream's Avatar
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    Default Re: Array Search Method

    Can you please show the code where create and fill the 'String[][] line' array?

  3. #3
    Super Moderator Norm's Avatar
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    Default Re: Array Search Method

    it gives me an array out of bounds exception
    Please copy and paste the full text of the error message here.
    It gives the bad index value and the source code line number where the error occurred.

  4. #4
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    Default Re: Array Search Method

    Quote Originally Posted by Kyuubi426 View Post
    The Array Size is line[6][5]. And When i search the Furthest surname (line[0][5])
    Remember that for an array of length N the last index is N-1.

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