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Thread: Search for number in array and return index

  1. #1
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    Default Search for number in array and return index

    I have created an array with five elements and populated it. I am trying to find a specific number within the array and output the index. If the number is not found, the output should be "False".

    Sample:
    // Created array
    int[] iArray = {3,2,1,4,5};
     
    //I'm looking for 5 in the array
    int x1 = 5;
     
    //loop to find 5 in the array
    for (int i = 0; i < iArray.length; i++){
          if (iArray[i] == x1){
          int position = iArray[i];
          System.out.println("Index found: " + position);
          }
    }

    I know that the index is in fact 4, but when I run this code, it says 5. No matter what I change int x1 to, it will return the value of x1. What am I doing wrong?


  2. #2
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    Default Re: Search for number in array and return index

    Duplicate post over at Java Forums. Already answered.

  3. The Following User Says Thank You to Junky For This Useful Post:

    Kevinius (March 24th, 2011)

  4. #3
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    Default Re: Search for number in array and return index

    I originally posted one this forum first. But yes, it was answered. I ended up tweaking it so that if there were multiple instances of that value, they would also be displayed. Thanks again.

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