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Thread: Input method

  1. #1
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    Default Input method

    I cannot implement this 'if' statement that I am trying to use on my console oriented text game.
    Basically, I thought there was an "input" method where the user would input a string of characters into the console.
    So I thought this would mean, if the user types in "Start", etc.
    Please bare with me, I am completely new to programming.

    if(input.equalsIgnoreCase("Start")){

    Apparently, it cannot find symbol "input".
    Can anybody help me out on what to write for an input class, for which users input a string of characters into the console, and it is read through these if statements.


  2. #2
    Member DavidFongs's Avatar
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    Default Re: Input method

    There is no implicit variable named input that holds user entered input.

    You can use the Java class Scanner (Java Platform SE 6) to read in input (That's a link). There is an example in the javadoc.

  3. #3
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    Default Re: Input method

    You can accept input like this:

    import java.util.Scanner;
     
    public class Testt
    {
    	public static void main(String[] args)
    	{
    		String input;
    		Scanner s = new Scanner(System.in);
     
    		System.out.println("Enter your input");
    		input = s.nextLine();
     
    		System.out.println(input);
    	}
    }

    Make sure to import the Scanner class.

  4. #4
    Member DavidFongs's Avatar
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    Default Re: Input method

    How is spoonfeeding the guy the answer better than linking him the javadoc and letting him figure it out? There is value in learning how to read a javadoc.

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