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Thread: Word filter assignment help

  1. #1
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    Question Word filter assignment help

    Hello, my assignment is to create a word filter that prompts for the forbidden word and replacement word, then scans an arbitrary amount of text and prints out the cleaned up version of the text, and also print the number of replaced words at the end. I understand the loop structure (I have a flow chart written out) but I am completely confused on the syntax of getting the program to scan individual words and then move on to the next after it gets a result. Do I need a variable that will act as a middle ground so it can do this or not?

    Also I only need to account for full words. If night was the forbidden word I wouldn't have to replace it within the word knight.

    Here's my code:
    import java.util.Scanner;
    public class Project2 {
     
    	public static void main(String[] args) {
     
                    String forbidword;
    		String replaceword;
    		int numreplaced = 0;
     
    		System.out.println("Enter word to be filtered out:");
    		Scanner keyboard = new Scanner(System.in);
    		forbidword = keyboard.next();
     
    		System.out.println("Enter replacement word:");
    		replaceword = keyboard.next();
     
    		System.out.println("Enter text to filter. Hit Control-Z to stop.");
     
    		while(keyboard.hasNext());
    		{
     
    			if (keyboard.next().equals(forbidword))
                            // I know /\ this /\ is wrong but I don't know what else to put there.
    			{
    				numreplaced = numreplaced + 1;
    				// Supposed to somehow move on to the next word here? 
    			}
     
                           else 
                           {
                                   // This will be the same as the 'if' part except without the counter
                           }
     
    		}	
     
    		System.out.println("A total of " + numreplaced + " words were replaced.");
    	}
     
    }
    Thank you!
    Last edited by helloworld922; September 15th, 2010 at 12:21 AM.


  2. #2
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    Default Re: Word filter assignment help

    Here's a sample output:

    Enter word to be filtered out:
    ni
    Enter word to replace it with:
    herring
    Enter text to filter. Hit Control-Z to stop.
    The wet dog ni
    sighs by the dry ni fire
    ni at night.
    The
    wet
    dog
    herring
    sighs
    by
    the
    dry
    herring
    fire
    herring
    at
    night.

    Replaced "ni" with "herring" 3 times.

  3. #3
    Super Moderator Norm's Avatar
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    Default Re: Word filter assignment help

    Read into a variable and then test it vs doing it all in one statement. It will allow for debugging and further processing of what was read in. Don't do it this way:
    if (keyboard.next().equals(forbidword))

  4. #4
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    Default Re: Word filter assignment help

    Quote Originally Posted by Norm View Post
    Read into a variable and then test it vs doing it all in one statement. It will allow for debugging and further processing of what was read in. Don't do it this way:
    if (keyboard.next().equals(forbidword))
    I agree with Norm. I have always found that it is easier to debug and understand my programs when I create variables for things, whether I'm going to use it more than once or not. It is a good thing to do, especially in larger programs.

    You would do something like:
    String var = keyboard.next();
    System.out.println(var);
    if (var.equals(forbidword))

    It is more lines of code, but it makes it easier to debug and fix when things go wrong.


    Also, from a personal stylistic point of view, I recommend always initializing variables with basic values. I know some types have defaults, but I prefer to always initialize when I create.
    For ints: I usually set them to -1, since that is usually used as an anomaly number.
    For Strings: I usually set them to "" (empty String), since that will results in an empty value.
    For Objects: I usually set them to null, since that indicates I never gave it a value.

    I do this because it prevents compiler errors about not initializing variables when your variable setting is condition based. For you, this isnt the case, but it is a good thing to start doing.

    So, instead of this:
    String forbidword;
    String replaceword;
    int numreplaced = 0;
     
    System.out.println("Enter word to be filtered out:");
    Scanner keyboard = new Scanner(System.in);
    forbidword = keyboard.next();
     
    System.out.println("Enter replacement word:");
    replaceword = keyboard.next();

    I would say:
    String forbidword = "";
    String replaceword = "";
    int numreplaced = 0;
     
    System.out.println("Enter word to be filtered out:");
    Scanner keyboard = new Scanner(System.in);
    forbidword = keyboard.next();
     
    System.out.println("Enter replacement word:");
    replaceword = keyboard.next();

    Once against, entirely stylistic, but it is how I prefer to do it.
    Last edited by aussiemcgr; September 15th, 2010 at 07:51 AM.

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