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Thread: "possible loss of precision", except not, code doesn't work, simple question

  1. #1
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    Default "possible loss of precision", except not, code doesn't work, simple question

    Hello,

    I'm trying to make my array as compact as possible. since a calculation will not go above 60, i used byte data type, but the compiler says 'possible loss of precision' and then doesn't run the array. Here is the code fragment:

    tarray=new byte[6][10];
    		for(byte y=0;y<6;y++){
    			for(byte x=0;x<10;x++){
    				tarray[y][x]=(y*10)+x;
    				System.out.println("tilearray "+y+","+x+": "+tarray[y][x]);
    			}
    		}

    The following very similar code has the same error, but outputs the value:

    byte six=6;
    byte ten=10;
    byte mul=six*ten;
    System.out.println(mul);

    So why doesn't my array output the information.


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: "possible loss of precision", except not, code doesn't work, simple question

    Tell the compiler you know what you are doing by casting the int result to byte:
    int var = (byte) (int expression here);

  3. #3
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    Default Re: "possible loss of precision", except not, code doesn't work, simple question

    thank you Norm, it's fixed

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