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Thread: Linear Search

  1. #1
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    Default Linear Search

    Hey Guys,

    I've been stuck on part on parts 5-6 for my lab. I have an array that holds random integers and have sorted them. I am using linear search to locate an integer.

    I would like to receive some help on parts 5 and 6 please.

    Now, I don't know how to calculate the average-running time in code. I am also confused on part 6 when they ask me to repeat for 500 times.
    Attached Images Attached Images

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Linear Search

    Please type in the text so it is readable. The image is not readable and it is not possible to copy any text from an image to include in a response.

    Also be sure to wrap any code you post in code tags.

    Also posted here: http://www.dreamincode.net/forums/to...linear-search/
    and here: https://coderanch.com/t/691466/java/...Search#3245817
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
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    Default Re: Linear Search

    Thank you for the information.

    Here is a direct link to the prompt referencing my question:

    https://i.imgur.com/2juMme4.png

    import java.util.ArrayList;
    import java.util.Collections;
    import java.util.Random;
    import java.util.Scanner;
     
    public class LAB1 {
    	private int userNumber;
    	private ArrayList<Integer> userList = new ArrayList<Integer>();
    	private ArrayList<Integer> userCounter = new ArrayList<Integer>();
     
    	private static Random rand = new Random();
    	private boolean bool = false;
     
    	Scanner input = new Scanner(System.in);
     
    	public ArrayList<Integer> randomArray() {
     
    		while(!bool) {
    			System.out.println("Enter a positive number: ");
    			userNumber = input.nextInt();
    			if(userNumber > 0) {
    				bool = true;
    			}
    		}
    		for(int i = 0; i < userNumber; i++) {
    			int randomNumber = rand.nextInt(1000 + 1 + 1000) - 1000;
    			userList.add(randomNumber);
    			userCounter.add(i);
    			Collections.sort(userList);
    		}
     
    		//System.out.println(userCounter);
    		System.out.println(userList);
     
    		System.out.println("Pick a random number in the array: ");
    		Integer randomNumber = input.nextInt();
     
    		final long startTime = System.nanoTime();
     
    		//		for(int i = 0; i < 500; i++) {
     
    		linearSearch(userList, randomNumber);
    		//		}
    		final long duration = System.nanoTime() - startTime;
    		System.out.println(duration/1000000000 + " seconds ");
     
    		return userList;
    	}
     
     
    	public static int linearSearch(ArrayList<Integer> arrayList,Integer key) {
    		int counter = 0;
    		for( int i = 0; i < arrayList.size(); i++) {
    			if(key.equals(arrayList.get(i))) {
    				counter++;
    				if(counter <= 1)
    					System.out.println("number " + arrayList.get(i) + " was found " + counter + " time");
    				if(counter > 1) {
    					System.out.println("number " + arrayList.get(i) + " was found " + counter + " times");
    				}
    			}
    		}
    		return -1;
    	}
     
     
    	public static void main(String args[]) {
     
    		LAB1 obj = new LAB1();
     
     
    		obj.randomArray();
    	}
    }

  4. #4
    Super Moderator Norm's Avatar
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    Default Re: Linear Search

    Can you type in the text for the questions you have so it can be copied into a response if needed?
    If you don't understand my answer, don't ignore it, ask a question.

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