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Thread: parity

  1. #1
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    Default parity

    A bit string has odd parity if the number of 1's is odd. A bit string has even parity if the number of 1's is even. Zero is considered to be an even number, so a bit string with no 1's has even parity. Note that the number of 0's does not affect the parity of a bit string.
    Input File: parity.in The input consists of one or more strings, each on a line by itself, followed by a line containing only "#" that signals the end of the input. Each string contains 131 bits followed by either a lowercase letter 'e' or a lowercase letter 'o'.
    Output: Each line of output must look just like the corresponding line of input, except that the letter at the end is replaced by the correct bit so that the entire bit string has even parity (if the letter was 'e') or odd parity (if the letter was 'o').
    Sample Input Sample Output
    101e 1010
    010010o 0100101
    1e 11
    000e 0000
    110100101o 1101001010
    #





    * i try to solve it but its dosent work*
    Attached Images Attached Images

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    Default Re: parity

    t just start in this way this is right??
    how can i complete1Capture.jpg

  3. #3
    Member John Joe's Avatar
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    Default Re: parity

    Please don't post your code as image.The image is too small.
    Whatever you are, be a good one

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    Default Re: parity

    [/COLOR]how can i do it I am new here

  5. #5
    Member John Joe's Avatar
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    Default Re: parity

    Just post the code here

    Example

    public class Test{
         public static void main(String[] args)
        {
              // your code
        }
    }

    Use [CODE] tags to wrap your code.
    Last edited by John Joe; October 6th, 2017 at 11:09 AM.
    Whatever you are, be a good one

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