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Thread: help the noob pls

  1. #1
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    Default help the noob pls

    hi guys, i just started learning Java few days ago, so as u can guess i'm struggling. i wrote a small code but for some reason it aint working:

    import java.util.Scanner;
    public class Noob{
    static Scanner userInput= new Scanner(System.in);
    public static void main(String[] args){
    System.out.print("whats the shape? ");
    String a= userInput.nextLine();
    if(a.equals("triangle")){
    System.out.print("what's the length? ");
    int x= userInput.nextInt();
    System.out.print("what's the width? ");
    int y= userInput.nextInt();
    System.out.print("what u wanna know? ");
    String b= userInput.nextLine();
    if(b.equals("territory")){
    triTerr(x,y);
    }}}
    public static void triTerr(int x, int y){
    x= x*y/2;
    System.out.println("territory of triangle is "+ x);
    }}
    so as u can see it supposed to ask u the shape (triangle), then the length and the width, what u wanna know(territory) and it supposed to calculate and give u the territory of triangle. but for some reason it stuck and doesn't let u answer for "what u wanna know?"... what am i doing wrong??
    thnx for any help guys, it supposed to be a realy easy one.


  2. #2
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    Default Re: help the noob pls

    EDIT: I realized that you are leaving the newline character in the buffer.

    To fix it, put a userInput.nextLine(); after "what you wanna know?"
    Last edited by camel-man; October 8th, 2014 at 08:23 PM.

  3. #3
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    Default Re: help the noob pls

    Quote Originally Posted by camel-man View Post
    EDIT: I realized that you are leaving the newline character in the buffer.

    To fix it, put a userInput.nextLine(); after "what you wanna know?"
    Sorry i don't get it....can you type it?

  4. #4
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    Default Re: help the noob pls

    System.out.print("what u wanna know? ");
    userInput.nextLine();
    String b = userInput.nextLine();

  5. #5
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    Default Re: help the noob pls

    Quote Originally Posted by Synbios View Post
    System.out.print("what u wanna know? ");
    userInput.nextLine();
    String b = userInput.nextLine();
    sorry i missed ur answer, thnx. but i i didn't have to use "userInput.nextLine();" when dealing with String a, int x and int y, why do i have to use it with String b???
    Last edited by sash25; October 9th, 2014 at 03:39 AM.

  6. #6
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    Default Re: help the noob pls

    @sash25: Please post your code using code or highlight tags as explained near the top of this topic.

  7. #7
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    Default Re: help the noob pls

    import java.util.Scanner;
    public class Noob{
    static Scanner userInput= new Scanner(System.in);	
    public static void main(String[] args){
    System.out.print("whats the shape? ");
    String a= userInput.nextLine();
    if(a.equals("triangle")){
    System.out.print("what's the length? ");
    int x= userInput.nextInt();
    System.out.print("what's the width? ");
    int y= userInput.nextInt();
    System.out.print("what u wanna know? ");
    String b= userInput.nextLine();
    if(b.equals("territory")){
    triTerr(x,y);
    }}}
    public static void triTerr(int x, int y){
    x= x*y/2;
    System.out.println("territory of triangle is "+ x);
    }}

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