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Thread: COUNTING THE FREQUENCY OF NUMBERS INSIDE A TEXT FILE

  1. #1
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    Default COUNTING THE FREQUENCY OF NUMBERS INSIDE A TEXT FILE

    I have a source code here that counts the frequency of alphabetic characters and non-alphabetic characters (see the source code below).

    import java.io.*;
     
    public class letterfrequency {
    	public static void main (String [] args) throws IOException {
    		File file1 = new File ("letternumberfrequency.txt");
    		BufferedReader in = new BufferedReader (new FileReader (file1));
     
    		int nextChar;
    		int other = 0;
    		char ch;
     
    		int [] count = new int [26];
     
    		while ((nextChar = in.read())!= -1) {
    			ch = ((char)nextChar);
    			ch = Character.toLowerCase (ch);
    			if (ch >= 'a' && ch <= 'z')
    			  count [ch- 'a']++;
    			else
    			  other ++;
    		}
     
    		for (int i=0; i<26; i++){
    			System.out.printf ("%c = %d \n", i+ 'A', count [i]);
    		}
     
    		System.out.println ("Non-alphabetic characters: " + other);
    		in.close ();
    	}
    }

    But, let's just say that now I have the following characters in the text file, "letternumberfrequency.txt":
    71 geese - 83 cars - 58 cows- 64 mooses- 100 ants- 69 bangles- 90 molehills - 87 noses

    The numbers inside that text file would be considered as strings, am I right?
    But I want to extract the numbers so that I can also be able to count their frequency - not as individual digits but as whole numbers (that is how many "71", "83", "58", "64", etc. are there...).
    Would using "Double.parseDouble ()" help?


  2. #2
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    Default Re: COUNTING THE FREQUENCY OF NUMBERS INSIDE A TEXT FILE

    The numbers inside that text file would be considered as strings, am I right?
    it can be read as characters also, but in other class like scanner you can read it as int or double.

    Would using "Double.parseDouble ()" help?
    quiet tricky or you might end up confused with that way I think.

    here is one way using BufferedReader:
    1st - create a string. read each character in the file, once you encounter a digit, equate the string to that character
    2nd - then from that character, read the next characters and check if it is a number, if so concatenate it to the string you declared above, and once you read a non digit character, there you go the parsing part and then return to 1st step.

  3. The Following User Says Thank You to dicdic For This Useful Post:

    GregBrannon (April 7th, 2014)

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    Default Re: COUNTING THE FREQUENCY OF NUMBERS INSIDE A TEXT FILE

    If I am to insert your ideas in the code, would it look like the one below?

    import java.io.*;
     
    public class letternumberfrequency {
    	public static void main (String [] args) throws IOException {
    		File file1 = new File ("letternumberfrequency.txt");
    		BufferedReader in = new BufferedReader (new FileReader (file1));
     
    		int nextStr;
    		String str;
     
    		while ((nextStr = in.read())!= -1) {
    			String numberArray []= str.split ("[^\\d]+");
    		Map <String,integer> map = new HashMap <str,nextStr>();
    		for (String numberWord:numberArray){
    			integercounter = map.get (numberWord);
    			if (counter == null) {
    						counter = 0;
    			}
    			map.put (numberWord, counter +1);
    		}
    		for (String numbeWord:map.KeySet()){
    			System.out.println ("%s => %i", numberWord, map.get(numberWord));
    		}
    		in.close ();
    		}
    	}
    }
    Last edited by PC_flea; April 8th, 2014 at 07:17 AM. Reason: no code tags around included sample code

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    Default Re: COUNTING THE FREQUENCY OF NUMBERS INSIDE A TEXT FILE

    Also posted at: Counting the frequency of numbers inside a text file
    and
    http://forums.codeguru.com/showthrea...de-a-text-file
    If you don't understand my answer, don't ignore it, ask a question.

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