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Thread: Printing a Decimal Equivalent of a Binary Number

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    Default Printing a Decimal Equivalent of a Binary Number

    This problem is from Java How to Program 9e, chapter 4, exercise 31.

    It asks me to convert a binary number in to decimal.
    How to program this in java? I am not able to find an effective algorithm to convert in to Java.
    Help me, please.
    Thanks in advance.


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    Default Re: Printing a Decimal Equivalent of a Binary Number

    convert a binary number in to decimal.
    Are you talking about Strings that contain numbers as characters?
    For example: "0101" and "5"

    If not, please explain.

    The wrapper classes like Integer and Long have methods for converting a String to a number.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Printing a Decimal Equivalent of a Binary Number

    That's a problem. If I had to work with strings, I would have done it myself. We have to scan an integer value from CMD using nextInt(). The problem I am facing is that I am not able to find an algorithm to solve the problem.

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    Default Re: Printing a Decimal Equivalent of a Binary Number

    If I had to work with strings, I would have done it myself.
    Well, I think you're going to end up doing it yourself one way or the other, but if you could do it with a String object as an input, I don't see why you can't do it with an int value as an input.

    Sometimes you have to think up or create an algorithm to solve a problem, and you'll be better for it.

    Edit: The book pretty much gives you an algorithm: "[Hint: Use the remainder and division operators to pick off the binary number’s digits one at a time, from right to left. In the decimal number system, the rightmost digit has a positional value of 1 and the next digit to the left a positional value of 10, then 100, then 1000, and so on. The decimal number 234 can be interpreted as 4 * 1 + 3 * 10 + 2 * 100. In the binary number system, the rightmost digit has a positional value of 1, the next digit to the left a positional value of 2, then 4, then 8, and so on. The decimal equivalent of binary 1101 is 1 * 1 + 0 * 2 + 1 * 4 + 1 * 8, or 1 + 0 + 4 + 8 or, 13.]"

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    Default Re: Printing a Decimal Equivalent of a Binary Number

    Quote Originally Posted by Arslan Ahmad 656 View Post
    We have to scan an integer value from CMD using nextInt().
    First, Scanner has the useRadix(int radix) method. If you used this, the conversion binary-to-decimal would be a "breeze" and I guess this is not the goal of the exercise.
    So if you input a number like 10100101 it "seems" a binary number but it really is a decimal number. If you want to think it as a binary .... ok (for the purpose of the exercise). Simply think that each decimal digit is just only 0...1.

    Quote Originally Posted by Arslan Ahmad 656 View Post
    The problem I am facing is that I am not able to find an algorithm to solve the problem.
    As I said in last phrase, you have decimal digits. Use division/modulo operators by 10 to get all decimal digits. A minimal validation is possible, just to check that the value is only 0 or 1. Then you have binary digits 0/1 and you can start multiplying by 2 (or power of 2, depending on the approach) and adding together to obtain the converted decimal value.
    Last edited by andbin; February 28th, 2014 at 03:34 PM.
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    Default Re: Printing a Decimal Equivalent of a Binary Number

    integer value from CMD using nextInt()
    If the input to the problem is an int value in a variable, what do you want to do with the contents of that variable?
    Given the int value: 123 what do you want to get as output?
    If you don't understand my answer, don't ignore it, ask a question.

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    Thumbs up Re: Printing a Decimal Equivalent of a Binary Number

    Quote Originally Posted by GregBrannon View Post
    Well, I think you're going to end up doing it yourself one way or the other, but if you could do it with a String object as an input, I don't see why you can't do it with an int value as an input.

    Sometimes you have to think up or create an algorithm to solve a problem, and you'll be better for it.

    "
    What would I do if it were a string. I would simply multiply the characters by the increasing powers of two to get the equivalent decimal number.

    --- Update ---

    Quote Originally Posted by Norm View Post
    Are you talking about Strings that contain numbers as characters?
    For example: "0101" and "5"

    If not, please explain.

    The wrapper classes like Integer and Long have methods for converting a String to a number.
    No, i am talking about integer input

    --- Update ---

    Quote Originally Posted by GregBrannon View Post
    Well, I think you're going to end up doing it yourself one way or the other, but if you could do it with a String object as an input, I don't see why you can't do it with an int value as an input.

    Sometimes you have to think up or create an algorithm to solve a problem, and you'll be better for it.

    Edit: The book pretty much gives you an algorithm: "[Hint: Use the remainder and division operators to pick off the binary number’s digits one at a time, from right to left. In the decimal number system, the rightmost digit has a positional value of 1 and the next digit to the left a positional value of 10, then 100, then 1000, and so on. The decimal number 234 can be interpreted as 4 * 1 + 3 * 10 + 2 * 100. In the binary number system, the rightmost digit has a positional value of 1, the next digit to the left a positional value of 2, then 4, then 8, and so on. The decimal equivalent of binary 1101 is 1 * 1 + 0 * 2 + 1 * 4 + 1 * 8, or 1 + 0 + 4 + 8 or, 13.]"
    Thanks Thanks Thanks!!!! A lot!!
    So foolish of mine. I just didn't read the hint; it is really an algorithm in itself. Thanks for reminding me. Solved.

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