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Thread: how to count occurance of numbers using java arrays

  1. #1
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    Default how to count occurance of numbers using java arrays

    out put comes from this program is:

    1 occurs 1 times
    13 occurs 1 times
    0 occurs 2 times
    9 occurs 0 times
    84 occurs 1 times
    0 occurs 2 times
    13 occurs 3 times
    2 occurs 1 times


    instead of:

    1 occurs 1 times
    13 occurs 3 times
    0 occurs 2 times
    9 occurs 2 times
    84 occurs 1 times
    2 occurs 1 times








    class occu{
    	public static void main(String arg[]){
    	int a[] = {1,13,0,9,9,84,0,13,13,2};
    	int i,j,count=0,temp,pretemp=-99999;
     
    		for(i=0;i<a.length;i++){
    		temp=a[i];
    		if(temp==pretemp)
    			continue;
    		else
    			for(j=0;j<a.length;j++)
    			if(a[j]==temp)
    			count++;
    			System.out.println( a[i]+  " OCCURS " +count+ " TIMES ");
    			count=0;
    			pretemp=a[i];
     
    		} // end for
    	} // end main
    } // end class
    Last edited by pbrockway2; January 1st, 2013 at 03:44 PM. Reason: code tags added


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: how to count occurance of numbers using java arrays

    How does the program accumulate the total counts for each number that is found?

    One problem I see with the code is missing {}s. You should always use {}s with loops and if statements to make sure you know what code goes in the loop or the if statement.

    Also for debugging the Arrays class's toString() method is useful to see what is in an array:
    System.out.println("an ID "+ java.util.Arrays.toString(theArrayName));
    If you don't understand my answer, don't ignore it, ask a question.

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