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Thread: Trying to create an alphabet-only string of any length

  1. #1
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    Default Trying to create an alphabet-only string of any length

    package test2problem3;
    import java.util.Random;
    public class Test2problem3 {
     
        public static void main(String[] args) {
     
     
     Random gen= new Random();
     
     String ranString="";
     int len=gen.nextInt(20)+1;
     int ranCode=0;
     
     int count = 0;
     
     while (count <len)
     {
         ranCode=gen.nextInt(58)+65;
         {
         if (((ranCode>=58)&&(ranCode<=64))||((ranCode>=91)&&(ranCode<=96)))
             System.out.print (ranString);
         else     
             ranString += (char)ranCode;
             count++;
     
             System.out.print(ranString);
         }    
     }
     
     
        }
    }

    I'm a beginner java student. this is what I got so far, with a knowledge I have.

    My Q's:
    1. There seems to be a slight pattern on some, is there any way to remove that?
    2. Is there any wrong/unnecessary parts to my code?
    3. Can I know a more efficient way of solving this type of problem, for a future reference?

    Thank you.


  2. #2
    Super Moderator jps's Avatar
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    Default Re: Trying to create an alphabet-only string of any length

    The indentation is poor.
    There should be some type of comment describing the purpose/use of the code.
    There is a set of brackets which can be deleted.

    ccCcCycCyMcCyMTcCyMTgcCyMTgecCyMTgeH
    wwRwRLwRLAwRLACwRLACwRLACwRLACVwRLACVbwRLACVbawRLA CVbarwRLACVbarSwRLACVbarSOwRLACVbarSOs

    YYFYFSYFSCYFSCfYFSCfFYFSCfFeYFSCfFeuYFSCfFeumYFSCf FeumhYFSCfFeumhB
    -----compare above to below------
    Y YF YFS YFSC YFSCf YFSCfF YFSCfFe YFSCfFeu YFSCfFeum YFSCfFeumh YFSCfFeumhB
    See why there is a pattern and why more than 20 characters are printed in each run.

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