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Thread: EASY [comparing two vectors of strings]

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    Default EASY [comparing two vectors of strings]

    Hello,
    i have two vectors containing strings.These two vectors they dont have the same length.
    I need to compare the strings between vector A and vector B ,and find sets of similar strings.
    At the end i need to delete the similar strings form vector A.

    Thank you for your help a priori.


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    Default Re: EASY [comparing two vectors of strings]

    You can check if a Vector of Strings contains a specified String. To do that, you envoke the Vector.contains(String) method (which returns a boolean). You would just need to loop through Vector A and envoke the contains() method on Vector B for each of Vector A's indexes.

    As for removing the similar Strings, you can loop through Vector A and use the Vector.remove(Object) method, and send it the Strings that you know are similar between the two Vectors. Or, if you were particularly lazy, you could call A.removeAll(B);. I believe that call *should* remove all the elements from Vector A that Vector B also has.
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    Default Re: EASY [comparing two vectors of strings]

    I think this answer will be helpful. I will try to work it out now.
    Below there is the output of the two vectors A and B as an example.
    i hope its helpful
    ----------(suitableForProcess>=1,hasTypeProfile>=1,hasTypicalConsumption>=1,hasLoadProfile>=1,去asTypicalConsumption.(Watt>=30,Watt<=30),去asTypeProfile.(MediumShift,Shiftable,TypeProfile,Profile),去asLoadProfile.(ConstantLoad,LoadProfile,Profile),叫uitableForProcess.(WatchingPhoto,MentalProcess,Process,EnvironmentTemperatureRegulation,Functionality,NormalSafetyLevel,SafetyLevelRegulation,MediumSecurityLevel,SecurityLevelRegulation,SoftLightLevel,LightLevelRegulation,PlayPhoto,!HighSecurityLevel,!LowSecurityLevel,!BrightLightLevel,!LowLightLevel,!NoLight,!NormalLightLevel))
    ----------(suitableForProcess>=1,isSuggestedForWeatherCondition>=1,isSuggestedForOutdoorLuminosity>=1,isSuggestedForTemperature>=1,可sSuggestedForOutdoorLuminosity.(HighLuminosity,OutdoorLuminosity,Weather,!LowLuminosity,!MediumLuminosity),可sSuggestedForWeatherCondition.(Sunny,WeatherCondition,Weather,!Cloudy,!PartlyCloudy,!Rain),可sSuggestedForTemperature.(Heat,Temperature,PhysicalStatus,Characteristic,!Cold,!Normal,!Refreshing,!Warmth),叫uitableForProcess.(BodyProcess,Process,EnvironmentTemperatureRegulation,Functionality,Cook,KitchenWork,KitchenLight,LightLevelRegulation,VentilationFunctionality,Eating))

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    Default

    Sorry misread... As started before iterate through one of the vectors and compare against the contents of the other.

    Michael.
    Last edited by MES Enterprises LLC; May 14th, 2012 at 06:20 PM.

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    Default Re: EASY [comparing two vectors of strings]

    Do you mean java.util.Vector when you say 'vector', or something else? Your problem sounds like it would be natural to solve it with java.util.Set:
    The Set Interface (The Java Tutorials > Collections > Interfaces)
    The method names will be familiar from aussiemcgr's post, but I suspect the implementations / performance (because java.util.Vector implements List) may vary greatly.

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    Default Re: EASY [comparing two vectors of strings]

    im sorry
    noob mistake
    i have two vectors containing ITEMS .At the end of the loops of the vectors i get 2 Items and i have to compare them .
    they look like this:

    ITEM A:---------->suitableForProcess>=1,hasTypeProfile>=1,(Watt>=30 ,Watt<=30),去asTypeProfile.(MediumShift,Shiftable, TypeProfile,Profile),去asLoadProfile.(ConstantLoad ,LoadProfile,Profile),叫uitableForProcess.(Watchin gPhoto,!NoLight,!NormalLightLevel)

    ITEM B:--------->suitableForProcess>=1,isSuggestedForWeatherCondit ion>=1,可sSuggestedForOutdoorLuminosity.(HighLumin osity,OutdoorLuminosity,Weather,!LowLuminosity,!Me diumLuminosity),可sSuggestedForTemperature.(Heat,T emperature,PhysicalStatus,Characteristic,!Cold,!No rmal,!Refreshing,!Warmth)

    After comparing those items,ill have to eliminate from Item A equal descriptions:
    in this example suitableForProcess>=1 must be eliminated

    **Note:those are semantic descriptions

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