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Thread: Decimal To binary Recursive conversion java?

  1. #1
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    Default Decimal To binary Recursive conversion java?

    My conversion is wrong there is an additional zero i would be very grateful if somebody could help me figure out what is wrong with my code i know it would be easier having one method for this but i want to use both a private method that takes a string buffer and an int and a public method that takes an int . code is below
    public class DecToBin
    {
    public static void main (String [] args)
    {
     
    System.out.println (" the value of 10 in binary is " + decimalToBinary (10));
    System.out.println (" the value of 1 in binary is " + decimalToBinary (1));
    System.out.println (" the value of 2 in binary is " + decimalToBinary (2));
    System.out.println (" the value of 5 in binary is " + decimalToBinary (5));
    System.out.println (" the value of -5 in binary is " + decimalToBinary (-5));
     
     
    }
     
    private static String decimalToBinary(int decimal, StringBuffer buffer)
    {
    buffer.append(decimal % 2);
    decimal /= 2;
    if (decimal == 0) return buffer.reverse().toString();
    else return decimalToBinary(decimal, buffer);
    }
    public static String decimalToBinary (int decimal)
    {
    StringBuffer buffer = new StringBuffer ();
    if (decimal < 0)
    return " - " + decimalToBinary (decimal* -1);
    else return decimalToBinary (decimal, buffer.append(decimal %2));
    }
    }


  2. #2
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    Default Re: Decimal To binary Recursive conversion java?

    Coz of your buffer.append(decimal%2) statement in
    public static String decimalToBinary (int decimal)
    {
    StringBuffer buffer = new StringBuffer ();
    if (decimal < 0)
    return " - " + decimalToBinary (decimal* -1);
    else return decimalToBinary (decimal, buffer.append(decimal %2));
    }
    It's also appending the zero in buffer this time.

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