Dear experts,

I am doing my assignment on finding how many numbers inNdigit satisfyKrequirement.

However, when i am testing the code, i could compile it but i couldn't execute it.

I am wondering if i made mistake in theas when i comment this out, my program is able to execute,though i didn't get the right output valuex = result + y; // add them together and return it.

Please kindly enlighten me.

Logic of my codes (example):

N = 15, K = 3

When N = 1, result = 0 + (N%10)

= 0 + (1%10)

= 1

y = N/10

= 1/10

= 0

x = 1 + 0

= 1

return x = 1

if (sumOfDigits(1) == K)

noOfNoSatisfy ++;

----------------------------------------------------

In the case of above, noOfSatisfy still remains as 0

-----------------------------------------------------

When N = 12, result = 0 + (N%10)

= 0 + (12%10)

= 2

y = N/10

= 12/10

= 1

x = 1 + 2

= 3

return x = 3

if (sumOfDigits(3) == K)

noOfNoSatisfy ++;

----------------------------------------------------

In the case of above, noOfSatisfy increase and plus 1

-----------------------------------------------------

import java.util.*; public class Digits { public static int sumOfDigits(int x) { int result =0; int y =0; //eg. Let x be 1 while(x>0){ // eg. 1 = 1 + (1%10); result = result + (x%10); //take the last digit of x // eg. 0 = 1/10 y = x/10; //take the first digit of x // eg. 1 = 1 + 0 x = result + y; // add them together and return it. } //eg. return 1 return x; } public static void main(String[] args) { int N, K, noOfNoSatisfy; Scanner sc = new Scanner (System.in); //eg. Let N be 1 N = sc.nextInt();//indicate Number //eg. Let K be 1 K = sc.nextInt();//indicate requirement number noOfNoSatisfy = 0; // to count how many time it matches with K (requirement number) for (int i = 1; i <=N; i++){ if(sumOfDigits(i) == K){//eg. 1 == K noOfNoSatisfy ++; // plus 1 to count } } System.out.println(noOfNoSatisfy); //print the number of count } }