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Thread: Arrays

  1. #1
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    Default Arrays

    import java.util.Scanner;  
    public class Max_Number {
      public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
     
        double[] myList = new double[6];
     
        double max = myList[0];
        for (int i = 1; i < myList.length; i++) {
          if (myList[i] > max) max = myList[i];
     
            System.out.print("Enter a number: ");
          myList[i] = input.nextDouble();
     
        }
     
     
        int countGreater = 0;
     
        for (int i = 0; i <myList.length; i++) {
            if(myList[i] > max)
            countGreater++;
        }
     
        System.out.println("The max is " + max);
        System.out.println("The number of values greater than the max is " + countGreater);
      }
    }
    The question asked me to write a program that reads 5 numbers, computes the max and finds out how many numbers are above the max. Please help!!!!!!


  2. #2
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    Default Re: Arrays

    With what?
    Improving the world one idiot at a time!

  3. #3
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    Default Re: Arrays

    Quote Originally Posted by ruffu054 View Post
    computes the max and finds out how many numbers are above the max.
    Simple. None!

    How can you have any numbers greater than the max number?
    Improving the world one idiot at a time!

  4. #4
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    Default Re: Arrays

    Its not giving me the correct output when run the program.

  5. #5
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    Default Re: Arrays

    I dont make up the problem I just try to do them

  6. #6
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    Default Re: Arrays

    still confused?????????????

  7. #7
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    Default Re: Arrays

    Then I suggest you seek clarification from your teacher. Given the numbers: 1 6 4 2, the largest number is 6 and there are no numbers bigger than 6. So the question does not make sense or you have misunderstood it.
    Improving the world one idiot at a time!

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