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Thread: BlackJack game rules if both bust

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    Default BlackJack game rules if both bust

    This is not a programming question, but I don't know the rules of BlackJack (card game). My question is, what happens in BlackJack when both player and the dealer goes over 21 (busts by going over)? Do they both fail? Who wins or loses if any? I need to know this to finish a Java project.

    Thanks,

    Tony


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    Super Moderator Norm's Avatar
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    Default Re: BlackJack game rules if both bust

    They play in sequence. If one busts, the other doesn't play and wins.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: BlackJack game rules if both bust

    Quote Originally Posted by Norm View Post
    They play in sequence. If one busts, the other doesn't play and wins.
    So, I always go first, if I go over, the dealer automatically wins even if the dealer is also over?

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    Default Re: BlackJack game rules if both bust

    How can the dealer go over if he hasn't taken any cards yet?
    All the hands are given 2 cards initially.
    Then the first player gets cards until ...
    Then the next player
    ...
    finally the dealer
    If you don't understand my answer, don't ignore it, ask a question.

  5. The Following User Says Thank You to Norm For This Useful Post:

    tonynsx (November 1st, 2013)

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    Default Re: BlackJack game rules if both bust

    Ok, thank you.

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