Take JavaPenguin's last advice and account for compareTo() == 0. This is the case where you have two objects which are equal. For properly designed compareTo() methods compareTo() == 0 means that the...
Type: Posts; User: helloworld922
Re: Need help fixing Binary Search Tree code
Take JavaPenguin's last advice and account for compareTo() == 0. This is the case where you have two objects which are equal. For properly designed compareTo() methods compareTo() == 0 means that the...