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Thread: how operator( && or || works).....

  1. #1
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    Default how operator( && or || works).....

    int k=5|6|7; how it works ....
    int k=4&5&6; how it work .....


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    Default Re: how operator( && or || works).....

    it's bit-wise operation: OR | and the other AND &

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    Default Re: how operator( && or || works).....

    Those are used to represent boolean operators. The && is used for AND statements and the || for OR statements.

    The expression "A || B" will return true if either A or B where "A && B" will only return true if both A and B are true.

    if(true || false)
    //code will run
    if(false || false)
    //code will not run
    if(true && false)
    //code will not run
    if(true && true)
    //code will run
    Check out my site -> tssolutions.net16.net

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    Default Re: how operator( && or || works).....

    Quote Originally Posted by Krumpir View Post
    Those are used to represent boolean operators. The && is used for AND statements and the || for OR statements.

    The expression "A || B" will return true if either A or B where "A && B" will only return true if both A and B are true.

    if(true || false)
    //code will run
    if(false || false)
    //code will not run
    if(true && false)
    //code will not run
    if(true && true)
    //code will run

    Sir, These Things i know .
    But my question is different

    e.g int k=5&4; give result k=4;

    but i fail to decide the result of int k=4&2&6;

    the same problem is with OR operator....

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    Junior Member Krumpir's Avatar
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    Default Re: how operator( && or || works).....

    Basic OR logic:
    x y x&y
    --------------
    1 0 | 0
    1 1 | 1
    0 1 | 0
    0 0 | 0

    In binary the numbers are represented as follow:
    4: 100
    2: 010
    6: 110

    The and operator will only return 1 when all 3 bits are 1.

    4: 1 0 0
    2: 0 1 0
    6: 1 1 0
    ----------
    0 0 0

    Thus the value of 4&2&6 is zero.

    Using the OR operator if only one bit needs to be 1 in order to return 1;

    4: 1 0 0
    2: 0 1 0
    6: 1 1 0
    ----------
    1 1 0

    Thus the value of 4&2&6 is 6.

    I hope you understand now, otherwise there is another explanation here: Bitwise operators in java
    Check out my site -> tssolutions.net16.net

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    Default Re: how operator( && or || works).....

    Quote Originally Posted by Krumpir View Post
    Basic OR logic:
    x y x&y
    --------------
    1 0 | 0
    1 1 | 1
    0 1 | 0
    0 0 | 0

    In binary the numbers are represented as follow:
    4: 100
    2: 010
    6: 110

    The and operator will only return 1 when all 3 bits are 1.

    4: 1 0 0
    2: 0 1 0
    6: 1 1 0
    ----------
    0 0 0

    Thus the value of 4&2&6 is zero.

    Using the OR operator if only one bit needs to be 1 in order to return 1;

    4: 1 0 0
    2: 0 1 0
    6: 1 1 0
    ----------
    1 1 0

    Thus the value of 4&2&6 is 6.

    I hope you understand now, otherwise there is another explanation here: Bitwise operators in java



    Thanks ......

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