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Thread: How To Ask the User to Enter Another Number Using the Number 1

  1. #1
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    Default How To Ask the User to Enter Another Number Using the Number 1

    Hello, I made a program called count vowels and I finished it but I want to ask the user to enter another number by pressing the number 1 and any other number entered would be invalid. I use JOptionPane, please help! Thanks. Here is the code:

    package countvowels;
    import javax.swing.JOptionPane;

    public class CountVowels {

    /**
    * @param args the command line arguments
    */
    public static void main(String args[]) {

    //Ask the user to enter a sentence and convert it to a string
    String text = JOptionPane.showInputDialog("Type a sentence and this program will tell you how many vowels there are (excluding 'y'): ");

    //Declare the counter and declare the vowels
    int count = 0;
    for (int i = 0; i < text.length(); i++) {
    char c = text.charAt(i);
    if (c=='a' || c=='e' || c=='i' || c=='o' || c=='u') {
    count++;
    }
    }

    //Determine the number of vowels in the sentence
    JOptionPane.showMessageDialog(null, "There are" + " " + count + " " + "vowel(s) in the phrase you entered.");

    //Ask the user if they would like to enter another word
    JOptionPane.showMessageDialog(null, "Press 1 to try a new phrase or press any other number to exit.");



    }
    }


  2. #2
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    Default Re: How To Ask the User to Enter Another Number Using the Number 1

    Sorry, I mean enter another word using the number 1.

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    Default Re: How To Ask the User to Enter Another Number Using the Number 1

    Hello Pettsa!
    You can place your code inside a do...while loop (since you want it to execute at least once). You can then ask the user for an int like you do when you ask for a sentence, parse the String to an int with one of the Integer's methods and have your loop going for as long as user enters 1.

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    Default Re: How To Ask the User to Enter Another Number Using the Number 1

    Thanks, but what do i state if if they hit another number?

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    Default Re: How To Ask the User to Enter Another Number Using the Number 1

    Quote Originally Posted by Pettsa View Post
    Thanks, but what do i state if if they hit another number?
    I'm not sure I understood your question.
    If the user inputs another number the program will stop since it will keep looping only if the user enters 1.
    Why don't you try it and see what will happen?

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    Default Re: How To Ask the User to Enter Another Number Using the Number 1

    Ok, I got the loop done but.... when I hit 1 the first time, it works well but when the program runs the second, I hit 1 to the second time and it exits the program. I don't know why.

    Here is the code:

    package countvowels;
    import javax.swing.JOptionPane;

    public class CountVowels {

    /**
    * @param args the command line arguments
    */
    public static void main(String args[]) {

    //Ask the user to enter a sentence and convert it to a string
    String text = JOptionPane.showInputDialog("Type a sentence and this program will tell you how many vowels there are (excluding 'y'): ");

    //Declare the counter and declare the vowels
    int count = 0;
    for (int i = 0; i < text.length(); i++) {
    char c = text.charAt(i);
    if (c=='a' || c=='e' || c=='i' || c=='o' || c=='u') {
    count++;
    }
    }

    //Determine the number of vowels in the sentence
    JOptionPane.showMessageDialog(null, "There are" + " " + count + " " + "vowel(s) in the phrase you entered.");

    //Declare variables
    int i = 0;

    //Ask the user if they would like to enter another word from a string and convert to a double
    String inputNumber = JOptionPane.showInputDialog("Press 1 to try a new phrase or press any other number to exit.");
    i = Integer.parseInt(inputNumber);

    do
    {
    i++;
    JOptionPane.showInputDialog("Type a sentence and this program will tell you how many vowels there are (excluding 'y'): ");
    JOptionPane.showMessageDialog(null, "There are" + " " + count + " " + "vowel(s) in the phrase you entered.");
    JOptionPane.showInputDialog("Press 1 to try a new phrase or press any other number to exit.");

    }
    while (i == 0);
    {

    if (i == 1) {
    JOptionPane.showInputDialog("Type a sentence and this program will tell you how many vowels there are (excluding 'y'): ");
    }

    else
    System.exit(i);
    }
    }
    }

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    Default Re: How To Ask the User to Enter Another Number Using the Number 1

    Quote Originally Posted by Pettsa View Post
    Ok, I got the loop done but.... when I hit 1 the first time, it works well but when the program runs the second, I hit 1 to the second time and it exits the program. I don't know why.
    I don't think ity works well when you hit 1 the first time. The vowels counting is incorrect because you don't count them at all, you only print the number of vowels (count) of the first sentence. You should check again the logic of your program. It should be something like;
    do
       prompt the user to enter a sentence
       count vowels
       print #vowels
       ask if he wants to continue
    while (he wants to continue)

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