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Thread: java Loop program to place distinct value in a row, column and diagonal

  1. #1
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    Default java Loop program to place distinct value in a row, column and diagonal

    Hi,

    I'm novoice to java. I'm trying a program for place 8 X’s on the board with 64 boxes(8*8 matrix) in such a way that:
    1. there is at the most one X in any box
    2. no two X’s are on the same row
    3. no two X’s are on the same column
    4. no two X’s are on the same diagonal
    Write a Java application program that takes a brute-force approach using random
    number generation to find one such placement and display it on the screen.
    Basically, the program will do the following until it finds a solution:
    1. set n = 1
    2. For n =1 to 8
    a. check if there are any other boxes where an X can be placed without violating any
    of the constraints that we have specified above. if no, go to step 1
    b. choose a random box to place the nth X
    c. find out if placing an X in that box violates any of the constraints that we have
    specified above.
    If no, place the nth X in that box, increment n by 1.

    Below is the code, that i have tried so far...Please help me to finish this program as soon as possible...Please Help me...It's very urgent

    import java.util.Random;
     
    public class Assignment1_HondalCarlos {
    static int res;
     
    public static void main(String[] args)
    {
     
    char[][] board = new char[8][8];
    Random randomGenerator = new Random();
    int randomRow =0;
    	int randomColumn=0;
    for(int a=0;a<8;a++)
    {
    	for(int b=0;b<8;b++)
    	{
    		board[a][b]='-';
     
    	}
     
    }
    for(int a=0;a<8;a++)
    {
    	for(int b=0;b<8;b++)
    	{
    		System.out.print(board[a][b] +"  ");
    	}
    	System.out.println("  ");
    }
    for(int n = 0; n < 8; n++)
    {
    	 randomRow = randomGenerator.nextInt(8);
    	 randomColumn = randomGenerator.nextInt(8);
    	boolean test = false;
     
    testconstraints(board, randomRow, randomColumn);
    	if(res==0)
    	{
    		board[randomRow][randomColumn] = 'X';
     
    	}
     
     
    }
     
    for(int j=0;j<8;j++)
    {
    	for(int k=0;k<8;k++)
    	{
     
    		System.out.print(board[j][k] +"  ");
    	}
    	System.out.println("  ");
    }
     
    }
     
    public static int testconstraints(char[][] board,int rowCheck, int colCheck)
    {
    	System.out.println("Row :" + rowCheck + " Column : " + colCheck);
     
    			if(board[rowCheck][0]=='X' || board[rowCheck][1]=='X' ||board[rowCheck][2]=='X' ||board[rowCheck][3]=='X' ||board[rowCheck][4]=='X' ||board[rowCheck][5]=='X' ||board[rowCheck][6]=='X' ||board[rowCheck][7]=='X' )
    			{
    				if(board[0][colCheck]=='X' || board[1][colCheck]=='X' || board[2][colCheck]=='X' || board[3][colCheck]=='X' || board[4][colCheck]=='X' || board[5][colCheck]=='X' || board[6][colCheck]=='X' || board[7][colCheck]=='X'  )
    				{
    					res= 1;
    				}
    			}
    			else
    			{
    				res = 0;
    			}
    return 0;
    }
    }


  2. #2
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    Default Re: java Loop program to place distinct value in a row, column and diagonal

    Hello Experts,

    Please reply me...I really need to solve this program soon...
    Please somebody guide to finish this program as soon as possible..

    Please experts help me..It is very very urgent..

  3. #3
    mmm.. coffee JavaPF's Avatar
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    Default Re: java Loop program to place distinct value in a row, column and diagonal

    What is your problem exactly? What does work? What doesn't work?

    You need to take things one step at a time.
    Please use [highlight=Java] code [/highlight] tags when posting your code.
    Forum Tip: Add to peoples reputation by clicking the button on their useful posts.

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    Default Re: java Loop program to place distinct value in a row, column and diagonal

    loop program

    Duplicate post
    Improving the world one idiot at a time!

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