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Thread: Operator % cannot be applied to java.lang.String,int?

  1. #1
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    Default Operator % cannot be applied to java.lang.String,int?

    i cant help myself...
    import java.io.*;
     
    public class A
     
    {
    public static void main (String arum[])throws IOException{
    BufferedReader tag=new BufferedReader (new InputStreamReader(System.in));
     
    String a;
    int b;
     
     
     
    System.out.println();
    System.out.println();
    System.out.println();
     
    System.out.println("Enter any number: ");
    a=tag.readLine();
     
    b=a%2;
     
    System.out.println();
    System.out.println();
     
     
     
    	if(b==1)
                    {
    		System.out.println("The number you entered is ODD");
    		}
     
    	else if(b<0)
                    {
    		System.out.println("The number you entered is NEGATIVE");
    		}
            else if(a==0)
    		{
    		System.out.println("The number you entered is ZERO");
    		}
            else if(b==0)
                    {
    		System.out.println("The number you entered is EVEN");
    		}
             else 
                    {
                    System.out.println("You have entered INVALID VALUES");
                    }
    	}
    }


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Operator % cannot be applied to java.lang.String,int?

    What are you trying to do with a String and the % operator?

    What would the results of "hi there" % 4 be?
    It makes no sense.

    If the String contains numeric digits: "123" then use an Integer class method to convert it to an int value that will work with the % operator.

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    Default Re: Operator % cannot be applied to java.lang.String,int?

    hmmm.. i use this?

    a=Integer.valueOf(String);

  4. #4
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    Default Re: Operator % cannot be applied to java.lang.String,int?

    Try it and see what happens:
    System.out.println("valueOf123=" + Integer.valueOf("123"));

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    Default Re: Operator % cannot be applied to java.lang.String,int?

    how can i declare that the value entered is invalid? it now can say ODD, NEGATIVE, EVEN, ZERO
    import java.io.*;
     
    public class A
     
    {
    public static void main (String arum[])throws IOException{
    BufferedReader in=new BufferedReader (new InputStreamReader(System.in));
     
     
    int a;
     
     
     
    System.out.println();
    System.out.println();
    System.out.println();
     
    System.out.println("Enter any number: ");
    a=Integer.parseInt(in.readLine());
     
     
     
    	System.out.println();
    	System.out.println();
     
     
     
    	if(a % 2 == 1)
    		{
    		System.out.println("The number you entered is ODD");
    		}		
     
    	else if(a % 2 < 0)
    		{
    		System.out.println("The number you entered is NEGATIVE");
    		}
    	else if(a == 0)
    		{		
    		System.out.println("The number you entered is ZERO");
    		}
    	else if(a % 2 == 0)
    		{
    		System.out.println("The number you entered is EVEN");
    		}
    	else 
    		{
    		System.out.println("You have entered INVALID VALUES");
    		}
    	}
    }
    Thanks for always being there Sir norms ^_^
    Last edited by helloworld922; July 12th, 2011 at 10:12 PM.

  6. #6
    Super Moderator Norm's Avatar
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    Default Re: Operator % cannot be applied to java.lang.String,int?

    how can i declare that the value entered is invalid
    First you must define what values are invalid.
    Then you can write code to detect them.

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    Default Re: Operator % cannot be applied to java.lang.String,int?

    i must say all characters except from 0-9/numbers should be invalid.

  8. #8
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    Default Re: Operator % cannot be applied to java.lang.String,int?

    What does your program do if you enter invalid data?

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    Default Re: Operator % cannot be applied to java.lang.String,int?

    I have a problem with the logic of your program. If a user enters -1 (which is ODD and NEGATIVE) the output will be ODD only.
    Improving the world one idiot at a time!

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