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Thread: Casting Theory

  1. #1
    Junior Member
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    Default Casting Theory

    I came across something interesting in my book and I'm unsure as to why this is happening. Here is some sample code:
    public class DividingWithDifferentTypes {
    	public static void main(String args[]) {
    		int iVar = 15;
    		long lVar = 2;
    		float fVar = 7.6f - iVar / lVar;
    		double dVar = 1L / lVar + fVar / lVar;
    		int result = (int) (100 * dVar);
    		System.out.println(iVar / lVar);
    		System.out.println((float) (iVar / lVar));
    		System.out.println(7.6f - (float) (iVar / lVar));
    		System.out.println(1L / lVar);
    		System.out.println(fVar / lVar);
    		System.out.println(100 * dVar);

    And here is the output:

    My confusion arises from the fact that the 4th output statement returns 0.5999999F instead of 0.6F.
    Why is this happening? I'm assuming it has to do with casting. Thank you in advance.

  2. #2
    Crazy Cat Lady KevinWorkman's Avatar
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    Default Re: Casting Theory

    Basically, it comes down to how decimals are stored in binary. You can only get so much precision out of it, so it's oftentimes off buy just a tiny bit. For more information, google "what every computer scientist should know about floating point arithmetic" for the go-to article explaining exactly what's happening.
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