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Thread: swapping nodes in a linked list

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    Default swapping nodes in a linked list

    i have a question regarding swapping nodes in a linked list. Suppose we have a linked list : 2->5->7->4->6

    Suppose we want to swap node with value 5 and node with value 4. What do we pass as parameters to our function? If my function is defined as swap(Node n1, Node n2), what do i pass in my main function so it knows which nodes to swap?


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    Default Re: swapping nodes in a linked list

    Is the linked list class your code or the one from the Java SE? That would determine what methods are available to do the swap.

    You ask the questions.
    How to swap elements in the list based on the contents of the objects in the list: values 4 and 5
    How to swap n1 and n2.
    In the first case pass the contents of the objects
    In the second case pass references to objects

    The swap method(s) would have to search the list to find the two elements to be swapped and then could swap them depending on the methods available.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: swapping nodes in a linked list

    im using my own code......lets say i have my function: swap(Node n1, Node n2);
    since i want to swap nodes, how do i pass the nodes that i want to swap? if i want to pass node with content 5 and node with content 4, what do i pass as my parameters?
    what i did was pass function that look for nodes at specific indexes: if list is 2->5->7->4->6 and i want to swap node with content 5 and node with content 4, then i call my function as: swap(findNodeAtIndexN(1), findNodeAtIndexN(3))
    is there a simpler way to pass nodes in my swap function?

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    Default Re: swapping nodes in a linked list

    What methods does your linked list have that could be used for swapping?

    how do i pass the nodes that i want to swap
    As arguments to the swap method: swap(node1, node2);

    with content 5 and node with content 4
    As args: swap(5,4);

    If the findNodeAtIndexN method returns a Node object, then
    swap(findNodeAtIndexN(1), findNodeAtIndexN(3));
    would be calling the same method as the first one above: swap(node1, node2);

    I don't know what would be simpler way to specify what nodes to swap than those two methods.
    If you don't understand my answer, don't ignore it, ask a question.

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