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Thread: help with console input strnig....

  1. #1
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    Default help with console input strnig....

    i have a console input class that works on buff = new BufferedInputStream(System.in);
    it returns a string of the input ....
    now when i use it the string that comes back is in some way different .
    let say a input "abc" if i write the string it well print "abc" but if i use input.equals( "abc") it is false
    here is my main...

    import java.io.*;
    import java.util.*;
     
    public class DemoGeter
    {
    public static void main(String[] args)
       {
        String inputS = new String(ConsoleInput.readLine());
     
        String result = ReplaceString.replaceString(inputS); // replaces some of the chars (file separator)  prints 
                                                                                                the result.....
        System.out.println(result);
     
        String seeIf = new String("M:/iPod_Control/Music");
     
        System.out.println(seeIf);
     
        if (seeIf.equals(result))
        System.out.println("same");
        else 
        System.out.println("not same");


    here is the output for input " M:/iPod_Control/Music"

    M:/iPod_Control/Music \\input line
    M:/iPod_Control/Music \\ replaceString result and return string
    M:/iPod_Control/Music \\ seeIf is the string i what to get to....
    not same \\ if statement shows that string are different
    no files false


  2. #2
    mmm.. coffee JavaPF's Avatar
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    Default Re: help with console input strnig....

    Hey,

    I edited the code slightly so it compiled and this works as expected:

    import java.io.*;
    import java.util.*;
     
    public class DemoGeter
    {
    public static void main(String[] args)
       {
        String inputS = "abc";
     
        String result = inputS;
     
        System.out.println(result);
     
        String seeIf = new String("M:/iPod_Control/Music");
     
        System.out.println(seeIf);
     
        if (seeIf.equals(result))
        System.out.println("same");
        else 
        System.out.println("not same");
     
       }
    }

    I think the problem is with ReplaceString.replaceString(inputS);

    Can we see this method?
    Please use [highlight=Java] code [/highlight] tags when posting your code.
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  3. #3
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    Default Re: help with console input strnig....

    Just as a side note, please don't use new for a String, you might end up messing up.
    just use
    String seeIf = "M:/iPod_Control/Music";
    There would be disastrous results if u start using new for String, especially when you use == for comparing such strings rather than equals.

    Acumen,
    Lucid forums

  4. #4
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    Default Re: help with console input strnig....

    i don't think that the problem is with replacestring method because even if i change the if statement to
    if (seeIf. equals(inputS)) the same output is shown ..... but here it is ...
     
    import java.io.*;
    class ReplaceString
    {
    static int count = 0;
    public static String replaceString(String str)
      {       
             if (str.indexOf(":") == 1 && count == 0)
                {
                 count ++;
                 String str1 = str.substring(2,str.length());
                 String str2 = replaceString(str1);
                 str1 = str.substring(0,2);
                 String str3 = str1.concat(str2);
                 return str3;
                }  
     
             String re = str.replace( '\\', File.separatorChar);
             str = new String(re.replace( '/', File.separatorChar));
             re = new String(str.replace( ':', File.separatorChar));
             if (File.separatorChar == '\\')
             { 
             String n = new String(re.replace('\\', '/'));
             return n;
             }
     
        return re;
       }
    }

  5. #5
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    Default Re: help with console input strnig....

    well thanks every one i found out the problem there was some how some space that got caught at the end of the input when the input stream ended so all i did is add a trim() method to the return from the consoleInput method and it worked ...

  6. #6
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    Default Re: help with console input strnig....

    Quote Originally Posted by mdstrauss View Post
    well thanks every one i found out the problem there was some how some space that got caught at the end of the input when the input stream ended so all i did is add a trim() method to the return from the consoleInput method and it worked ...
    Ahhhh I was going to suggest that! Wanted to check the other things first. Glad you solved your problem
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