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Thread: Input error. Program skips several lines of code during execution.

  1. #1
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    Default Input error. Program skips several lines of code during execution.

    I am a beginner experimenting with user input and data types. My program, chatbot, has an error in it that I cannot find. When run, it collects my name and age, but then skips right over prompting for my favorite pasttime, as if I had pressed the "enter" key prematurely. It then goes to the next question. I believe that this error has something to do with my use of the 'byte' data type, but I don't know how to fix it.

    Here is my code:

    import java.util.Scanner;
     
    public class ChatBot {
     
    	public static void main(String[] args) {
    		Scanner in = new Scanner(System.in);
     
    		String name;
    		System.out.print("What is your name? ");
    		name = in.nextLine();
    		System.out.println("Hello, " + name + ".  ");
     
    		byte age;
    		System.out.print("How old are you?  ");
    		age = in.nextByte();
     
                    \\ Here is where it skips ahead in the code.
     
    	        System.out.println("So, you're " + age + " years old?  ");
     
    		String hobby;
    		System.out.print("What is your favorite hobby?  ");
    		hobby = in.nextLine();
    		System.out.println("So, you like " + hobby + "?  ");
    		\\ Here is where it picks up.  It does prompt for my mother's name, but not my hobby.
     
    		String mother;
    		System.out.print("What is your mother's name?  ");
    		mother = in.nextLine();
    		System.out.println("So, your mother's name is " + mother + ".  ");
    	}
     
    }

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Input error. Program skips several lines of code during execution.

    had pressed the "enter" key prematurely.
    That is because of a Scanner class feature. The next... (except nextLine) methods leave the lineend char in its buffer. The nextLine method reads and returns that lineend char as an empty line. The fix is to call the nextLine method after any calls to next... methods to clear the lineend char.
    If you don't understand my answer, don't ignore it, ask a question.

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