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Thread: calling up and printing an arrayHistogram

  1. #1
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    Default calling up and printing an arrayHistogram

    I'm writing a method called arrayhist that has an array of 30 random integers and returns a new histogram array that has 11 elements with this content:
    element 0 -- number of elements in the array that are <= 0
    1 -- number of elements in the array that are == 1
    2 -- number of elements in the array that are == 2
    ...
    9 -- number of elements in the array that are == 9
    10 -- number of elements in the array that are >= 1
    0
    Also, how do I get my solution to only traverse the array once?
    public static int[] arrayHist(int[] arr) {
    		int[] hist = new int[11];
     
    		for(int i = 0; i < arr.length; i++) {
    			int val = arr[i];
    			if (val <= 0) {
    				hist[0]++; 
    			} else if (val >= 10) {
    				hist[10]++;
    			} else {
    				hist[val]++; 
    			}
    		}
    		return hist;
    	}
    I'm having trouble with calling and printing the method from main.


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: calling up and printing an arrayHistogram

    I'm having trouble with calling and printing the method from main.
    Post the code that shows the problem or explain what the problem is.
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
    Junior Member didingnuriska's Avatar
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    Default Re: calling up and printing an arrayHistogram

    static method like yours "public static int[] arrayHist(int[] arr)" can be used in a dynamic method main
    you need to change the method like this public int[] arrayHist(int[] arr)
    and then you can add one method to printed like "public void printHist(int[]hist)"
    and then in the main method you need to instantiated the class to an object, then calling both method

    public static void main(String []ag){
    int arr[]=new in arr[fixedNumber];//define
    int hist[]=new int[fixedNumber];
    NewClass a= new NewClass();
    hist=a.arrayHist(arr);
    a.printHist(hist);
    }

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