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Thread: Index Out Of Bounds

  1. #1
    Java kindergarten chronoz13's Avatar
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    Default Index Out Of Bounds

        public static void main(String[] args) {
     
            int[] divisors = new int[0];
     
            int number = 7,
                divisibilityCount = 0;
     
            for (int x = 1; x <= number; x++) {
     
                if (number % x == 0) {
     
                    divisibilityCount++;
                    divisors = new int[divisibilityCount];
                }
     
                for (int i = 0; i <= divisors.length - 1; i++) {
     
                    if (divisors[i] == 0) {
     
                        divisors[i] = x;
                    }
                    else {
     
                        divisors[i + 1] = x;
                    }
                }
            }
     
     
     
            for (int x = 0; x <= divisors.length - 1; x++) {
     
                System.out.println(divisors[x]);
            }
        }

    can figure it out....... help pls
    Last edited by chronoz13; December 28th, 2009 at 03:13 AM.


  2. #2
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    Default Re: Index Out Of Bounds

    Your 'for' continuation expression pretty much guarantees trying to access past the end of the array. Array indexes start at 0 and end at length - 1, so the continuation condition should normally be i < length. Initialising 'divisors' to a zero length array doesn't help - what's the point of that?

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