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Thread: Selection Sorting of Data type (Char)

  1. #1
    Java kindergarten chronoz13's Avatar
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    Default Selection Sorting of Data type (Char)

    public class CharSortTest {
     
        public static void main(String[] args) {
     
            char[] letters = {'j', 'a', 'z', 'y', 'x'};
     
            char min = 0;
     
            char swap = 0;
     
            for (int x = 0; x <= letters.length - 1; x++) {
     
                min = letters[x];
     
                for (int i = x + 1; i <= letters.length - 1; i++) {
     
                    if (letters[i] < min) {
     
                        min = letters[i];
                    }
                }
     
                if (letters[x] != min) {
     
                    swap = letters[x];
                    letters[x] = min;
                    min = swap;
                }
     
            }
     
            for (int p = 0; p <= letters.length - 1; p++) {
     
                System.out.println(letters[p]);
            }
        }
    }

    output:
    a
    a
    x
    x
    x

    i followed the logic of selection sorting.. i even checked the integer values of each character in my array
    but why is my program not sorting....


  2. #2
    Super Moderator helloworld922's Avatar
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    Default Re: Selection Sorting of Data type (Char)

    In selection sort, you don't want to keep track of the specific element, but rather it's index. This way you can perform the swap at the end. Also, there's no point in having the second if statement.

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