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Thread: Strings

  1. #1
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    Default Strings

    Write a Java program which reads in a string from the keyboard and then reports how many times each letter of the alphabet occurs within that string (ignoring case). It should also report how many non-letters are included in the string.

    Import B102.*;  
     
    class_prog1
    {
    public static void UserInput()
    {
    public String Data = new String()
    Screen.out.println("Please enter some characters values:");
    String.toLowerCase()
    Data=keybd.in.readchar();
    return Data;
    }
     
    public static void Calculate()
    {
    private char calcArray[] = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
    private int index;
    for(index=0; i<?; index++)
    }

    Just wondering If I'm on the right track for this program? Not to sure what else I should do
    Last edited by helloworld922; November 3rd, 2009 at 09:56 PM.


  2. #2
    Super Moderator helloworld922's Avatar
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    Default Re: Strings

    You can use the Character.isLetter() method:

    Also, fyi don't initialize strings by creating a new String. Strings are immutable, so doing so is just wasting time and memory.

    String data = "test string";
    int letterCount = 0;
    for (int i = 0; i < data.length(); i++)
    {
        if (Character.isLetter(data.charAt(i))
        {
              letterCount++;
         }
    }

  3. #3
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    Default Re: Strings

    thank you, I will attempt to start it

  4. #4
    Super Moderator helloworld922's Avatar
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    Default Re: Strings

    Oh, haha I didn't read the the first part of the question. For that portion, you can "cheat" by taking advantage of the underlying Unicode representation of characters. You will have to convert the string to all lower-case or all upper-case, though.

    int[] lettersCount = new int[26];
    char letter = 'a';
    lettersCount[(int)letter-'a']++;

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