Thread: Help with array code.

Very new to Java and am trying to create an array that has 5 integers and display them from first to last and last to first. What I have so far:

public class arrayex {
 
 
	public static void main (String[]args)
	{
	//create an array to hold 5 integers
   	int [] array = new int [5];
    int i=0;
	for(i=0;i<5;i++);
	System.out.println (array[i]);
    }
 
}

Here is the error message I am getting. not sure why.
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 5
at arrayex.main(arrayex.java:19)

1. You have declared an array that can hold 5 int values, but you haven't put any int values into it...
2. Your 'for' loop has a misplaced semi-colon at the end of the 'for...' statement, so the loop does nothing and the print of the array item happens after the loop has finished - when index i is 5, which is past the end of the array.

ETA: D'oh! copeg got there first...

Fixed the semicolon and added the int values.

[CODE] public static void main (String[]args)
{
//create an array to hold 5 integers
int [] array = new int [5];

int i=0;
array[i] = i + 1;
for(i=0;i<5;i++)

System.out.println (array[i]);
}

}[CODE]

Now, I get this output with only the number 1 and the rest zeros.

output:

1
0
0
0
0

Process completed.

Yes, that is what your code says to do: Put a value in element 0 of the array.

int i=0;   // set the value of i to 0
array[i] = i + 1;  // add 1 to i (1+0 = 1) and put that in element 0 of array

What do you want your code to do?

@ Norm, I want the code to display 5 integers from first to last then last to first.

If you want your array to have 5 integers in it, you have to put 5 integers into it. The compiler can't read your mind. You've told it to put one integer into position 0, so it put one integer into position zero.

I suggest you use one loop to put the integers into the array and a couple of loops to print them out again in first-to-last and last-to-first order.