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Thread: extend a simple class Contacts to have a new parameter called favorites

  1. #1
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    Default extend a simple class Contacts to have a new parameter called favorites

    Hi, I am a very beginner in Java. I have a simple class called contacts which is a class in a simple phonebook application. I would like to extend a class method to include an extra parameter in another class favorites. My attempt with my contact class below is giving errors. Can please someone help ?

    ************************************************** *****************************
    /** *
     * 
     */
    // Contacts Class
     
     
     
    public class Contacts {
     
        public String name;
        public String phoneNumber;
        public String nickname;
     
        public Contacts(String name, String phoneNumber) {
            this.name = name;
            this.phoneNumber = phoneNumber;
        }
     
         class Favorites extends Contacts 
          (String name, String phoneNumber,String nickname) {
            name = name;
            phoneNumber = phoneNumber;
            nickname = nickname;
         //
        }
     
        public String getName() {
            return name;
        }
     
        public String getPhoneNumber() {
            return phoneNumber;
        }
        public String getnickName() {
            return nickname;
        }
    }
    Last edited by Norm; August 28th, 2023 at 07:14 AM. Reason: Added / in ending code tag

  2. #2
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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    giving errors
    Please copy the full text of the compiler's error message and paste it here.

    See ending tag for proper coding:

    [code]
    **YOUR CODE GOES HERE**
    [/code]

    to get highlighting and preserve formatting.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    Sorry, Im using BlueJ. How do I get the error messages?

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    Sorry, I do not use BlueJ.
    To use the compiler From the command line, Enter: javac Contacts.java
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    Please bear with me, I'm a very beginner. Here are the error I get

    class Favorites extends Contacts ----> I get - { expected

    name = name; here I get identifier expected
    phoneNumber = phoneNumber;
    nickname = nickname;


    thank you so much.

  6. #6
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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    { expected
    The body of a class needs to be enclosed in {}s. Look at the Contacts class. It starts with:
    public class Contacts {
    and ends with a }

    When that is fixed, the other errors will change because the compiler got lost when it did not find the { for the class's body.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    I fixed the } issue but I still get errors now on the
    class favourites which are basically the same as previous. Can you help please?

    *********************************************

     
    public class Contacts {
     
        public String name;
        public String phoneNumber;
        public String nickname;
     
        public Contacts(String name, String phoneNumber) {
            this.name = name;
            this.phoneNumber = phoneNumber;
       }
     
        public String getName() {
            return name;
        }
     
        public String getPhoneNumber() {
            return phoneNumber;
        }
        public String getnickName() {
            return nickname;
        }
     
          public class Favorites extends Contacts 
          (String name, String phoneNumber,String nickname) {
            name = name;
            phoneNumber = phoneNumber;
            nickname = nickname;
     
        }
    }
    Last edited by Norm; August 28th, 2023 at 02:40 PM. Reason: Added missing / in ending code tag

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    The { goes after the class name. See the code for declaring the Contacts class:
    public class Contacts {
    What is the purpose of this line:
    (String name, String phoneNumber,String nickname)
    It looks like code for a constructor's or method's parameters.
    Again look at the code in Contacts:
    public Contacts(String name, String phoneNumber) {
    See how the name of the class is before (...)

    Did you write the code for the Contacts class or was it given to you to modify?

    Please look at this: https://docs.oracle.com/javase/tutor...classdecl.html
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    it was given to me to modify.

    I need to use it and show how I can use inheritance with the extends

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    Default Re: extend a simple class Contacts to have a new parameter called favorites

    Copy this link so you can use it to find java topics:
    http://docs.oracle.com/javase/tutori...ybigindex.html
    If you don't understand my answer, don't ignore it, ask a question.

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