Thread: Help me to figure out how code working

Hello everyone. Please tell me how working function

number = scanner.nextInt();
        if ((number & 0) == 1)`

Full code

package com.company;
 
import java.util.Scanner;
 
public class CheckParity {
    public static void main(String[] args) {
        int number;
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter number: ");
        number = scanner.nextInt();
        if ((number & 0) == 1) {
            System.out.println("Even number");
        } else {
            System.out.println("The number is not even");
        }
    }
}

--- Update ---

The most of I can't understand if ((number & 0) == 1)

Why we using number and &?

& its and. So why we do that?

Why we comparing number and 0? And why after priority () we use == 1?

Originally Posted by Jexly

Why we using number and &?

i don't think this code is correct. And regardless, using bitwise operators (&, | etc. ) only really makes sense if you are actually interested in individual bits.
Seems like the assignment here is to find out if a number is odd or even. So the proper test would be

if ( number % 2 == 0 )
{
     even
}
else
{
     odd
}