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Thread: finding a character from a given string value

  1. #1
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    Default finding a character from a given string value

    suppose the string is {"It's a wonderful forum. Are you looking for a new code? It's here. }

    i want to print the line like

    It's a wonderful forum.
    Are you looking for a new code?
    It's here.


    when the character will found "." or "?" then it will get a newline.


    i am looking for a code.

    thank you

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: finding a character from a given string value

    The String class's indexOf and substring methods could be used to find the end of each sentence and extract the sentence.
    Or a newline character could be inserted in the String following the locations of the . or ?
    If you don't understand my answer, don't ignore it, ask a question.

  3. The Following User Says Thank You to Norm For This Useful Post:

    sumon_bd (December 10th, 2021)

  4. #3
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    Default Re: finding a character from a given string value

    Quote Originally Posted by Norm View Post
    The String class's indexOf and substring methods could be used to find the end of each sentence and extract the sentence.
    Or a newline character could be inserted in the String following the locations of the . or ?
    would you like to give me the code. i have done it by own but there is a problem that ? mark goes to the next line. i need to add newline after the ? is printed

     
    package com.company;
     
    import java.util.Arrays;
     
    public class Main {
     
        public static void main(String[] args) {
            String str = "My name? it's me sumon";
     
            for(int i=0;i<str.length();i++)
            {
                if (str.charAt(i)=='?'){
                    System.out.print("\n");}
                System.out.print(str.charAt(i));
            }
     
                }
            }

  5. #4
    Super Moderator Norm's Avatar
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    Default Re: finding a character from a given string value

    a problem that ? mark goes to the next line.
    Print the newline AFTER printing the ?
    In other words: print the characters one by one and if the last one printed was a ? print a newline
    If you don't understand my answer, don't ignore it, ask a question.

  6. #5
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    Default Re: finding a character from a given string value

    i have forcefully solved it but still there is a problem of one space.

     
    package com.company;
     
    import java.util.Arrays;
     
    public class Main {
     
        public static void main(String[] args) {
            String str = "My name? it's me sumon";
     
            for(int i=0;i<str.length();i++) {
                if (str.charAt(i) =='?')
                {
                    System.out.print("?");
                    System.out.println();
                }
                else
                    System.out.print(str.charAt(i));
            }
     
     
            }
     
     
     
        }





    if possible give me a solution

    thank you.

  7. #6
    Super Moderator Norm's Avatar
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    Default Re: finding a character from a given string value

    there is a problem of one space
    Please describe in more detail. Is there one space too many or one space too few.
    Where is it?
    Copy the output and paste it here will comments about the space problem.
    If you don't understand my answer, don't ignore it, ask a question.

  8. The Following User Says Thank You to Norm For This Useful Post:

    sumon_bd (December 10th, 2021)

  9. #7
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    Default Re: finding a character from a given string value

    very interesting i have solved it.

    yes it's perfect now. there was a space counter into the string.

    now i will use this code into a large section .. try catch expection and reading file from a large text or pdf where it will make a para when it will get fullstop, question marks etc.


  10. #8
    Super Moderator Norm's Avatar
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    Default Re: finding a character from a given string value

    I am glad you have it working.
    If you don't understand my answer, don't ignore it, ask a question.

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