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Thread: why is this code giving value -48?

  1. #1
    Junior Member
    Join Date
    Apr 2021
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    Unhappy why is this code giving value -48?

    class HelloWorld {
    public static void main(String args[]) {
    System.out.println("hello world");
    byte a=40;
    byte b=50;
    byte c=(byte)(a*b);

  2. #2
    Super Moderator Norm's Avatar
    Join Date
    May 2010
    Eastern Florida
    Thanked 2,627 Times in 2,577 Posts

    Default Re: why is this code giving value -48?

    Because that is the int value contained in the c variable.
    a and b are treated as int values in the a*b expression. Print out the value of that expression to see what the results are:
          System.out.println((a*b) + " " + c);  // 2000 -48

    A signed byte uses 8 bits with the high order bit being the sign. =1 means negative
    If you don't understand my answer, don't ignore it, ask a question.

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