Thread: what is wrong with my code?

Hi. i was asked to put 3 numbers in array, and print them by order of who's the highest one.
I am a beginner, so this code is supposed to be simple (no strings what so ever..)

package Maaracim;
 
import MyPackage.MyConsole;
 
public class Maarachim6 {
 
	public static void main(String[] args) {
		// TODO Auto-generated method stub
 
 
 
	int []Array = new int [3];
	 Array[0]= (int)MyConsole.readInt("leave first  number");
	 Array[1]= (int)MyConsole.readInt("leave second  number");
	 Array[2]= (int)MyConsole.readInt("leave third number");
	 int smallest=Array[0];
	 int between=Array[0];
	 int highest=Array[0];
 
	for (int k = 0; k < Array.length; k++) {
 
		if (Array[k]<smallest) smallest = Array[k]; 
		if (Array[k]>highest) highest = Array[k]; 
		if ( Array[k]>smallest &&Array[k]<highest) between = Array[k];
 
			}
	System.out.println("highest number is "+highest);
	System.out.println("between number is "+between);
	System.out.println("smallest number is "+smallest);
 
	}}

Why do you think there is something wrong with the code?
Can you copy the contents of the command prompt window and paste it here to show what happens when the code is compiled and executed?
Add some comments describing what the problem is.

Please edit your post and wrap your code with code tags:

[code]
**YOUR CODE GOES HERE**
[/code]

to get highlighting and preserve formatting.

why the first one is not working.

Find the smallest and largest first, then find the middle one.

Yes, that is the way to do it.

Another way that is possible with only 3 elements to test is with nested if statements.
if a is low, order b and c
if b is low, order a and c
if c is low, order a and b