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How does java.util.Random work?
long seed = 314159265; Random rand = new Random(seed); int a = rand.nextInt(); seed = (seed * 0x5DEECE66DL + 0xBL) & ((1L << 48) - 1); int b = (int) (seed >>> (48 - 32));
Why is a not equal to b?
Here is the source code for nextInt() and next():
public int nextInt() { return next(32); } protected synchronized int next(int bits) { seed = (seed * 0x5DEECE66DL + 0xBL) & ((1L << 48) - 1); return (int) (seed >>> (48 - bits)); }
Last edited by Samkli; October 7th, 2014 at 04:10 AM.
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Re: How does java.util.Random work?
Welcome to the Forum! Thanks for taking the time to learn to post code correctly, and if you haven't already, please read this topic to see other useful info for newcomers.
Re: How does java.util.Random work?
Well a:
int a = rand.nextInt();
and b:
int b = (int) (seed >>> (48 - 32));
That's why they're not equal.
nextInt read next input, not next defined variable.
Re: How does java.util.Random work?
Could you explain what you mean by this?Originally Posted by TheBeginning
Re: How does java.util.Random work?
Look at the javadocs for the constructor Random(int seed)
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