Thread: Boolean return missing

So I'm trying to check if the new coordinates vs original coordinates are diagonal and 1 line further, and if there is a piece there(getNum()) if it's 2 lines further, so I'm trying to return a boolean value then.

so if it's the first if, it returns true, if it's the 2nd it returns true, then I say else for all other scenario's, and return false there, but my
compiler says my method is missing a return statement.

Where did I go wrong?
Thx

public boolean check(int[] d)
    {
        int x,y;
        x = loc[0][0];
        y = loc[0][1];
 
       int sx = d[0];
        int sy = d[1];
 
        if((sx == x+1))
        {
            if((sy == y +1) || (sy == y-1))
            {
                return true;
 
            }
 
        }
        else if((sx == x+2))
        {
 
            if((buttons[sx-1][sy-1].getNum() == true) || (buttons[sx-1][sy+1].getNum() == true) )
            {
                return true;
            }
        }
 
 
        else
        {
            return false;
        }
 
    }

Edit: used a local boolean and returned that after my if's.,

Originally Posted by GregBrannon

Just so you know . . . the compiler doesn't evaluate the if() statements to determine whether there is a logic path that will always result in a return. Rather, it sees that all return statements are contained in if() or if/else logic, and assumes that there may be NO path that results in a return. A way to satisfy the compiler is to always have a default return outside any other logic.

I don't understand your "local boolean" comment, but you could have simply added a return true or false as the last statement of the method OR evaluated whether the last 'else' condition was required and removed it if not.

Yeah, i've learned that now

By local I mean inside the method: boolean bool = false; then change the returns in the if statements with bool = true and at the end return bool;