Thread: Help me to round off double, PLEASE JAVA MASTERS!!!

SOURCE CODE:

Double a, b, c;

a = Double.parseDouble(txt1.getText());
b = Double.parseDouble(txt2.getText());
c = a + b;
txt3.setText(""+c);
}


SAMPLE OUTPUT:

1.234 + 1.23 = 2.464


PROBLEM:

How to round off that sum 2.464 as 2.46?
Will I put ".2f"?

You could multiply by 100, turn it to an integer and cast it back to double dividing by 100.

Good day sir!
Sir, I'm just a 17 year old Beginner Java Programmer, aiming to be become an expert someday.
Could you retype the code for me sir? Please Java Master!

What Cornix said is absolutely correct. I am no expert in Java. I just started java 4 or 5 months ago & i really liked this language. I dont know what you are trying to do with your code but casting is something i know.
I would like to give you a simple example or casting & you could try this and adjust according to your code:

double temp = 2.464;
float res = (int)(temp*100); //this (int) does the casting and removes the last digit as you want
res = res/100;
System.out.println(res);

Hope this helped you a little bit!

--- Update ---

& with your code i think this should work

Double a, b, c;

a = Double.parseDouble(txt1.getText());
b = Double.parseDouble(txt2.getText());
c = a + b;
float temp = (int)(c*100);
temp = temp/100;
text3.setText(""+temp);
}

Use Printf Statement for formatting text