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Thread: Network Program

  1. #1
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    Default Network Program

     
    // File Name : URLDemo.java 
    import java.net.*; 
    import java.io.*; 
    public class URLDemo 
    { 
    public static void main(String[] args) 
    {
    try { 
    URL url =new URL(args[0]); 
    System.out.println("URL is "+ url.toString()); 
    System.out.println("protocol is "+ url.getProtocol()); 
    System.out.println("authority is "+ url.getAuthority()); 
    System.out.println("file name is "+ url.getFile()); 
    System.out.println("host is "+ url.getHost()); 
    System.out.println("path is "+ url.getPath()); 
    System.out.println("port is "+ url.getPort()); 
    System.out.println("default port is "+ url.getDefaultPort()); 
    System.out.println("query is "+ url.getQuery()); 
    System.out.println("ref is "+ url.getRef()); 
    }catch(IOException e) 
    { 
    e.printStackTrace(); 
    } 
    } 
    }


  2. #2
    Administrator copeg's Avatar
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    Default Re: Network Program

    Do you have a question?

  3. #3
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    Default Re: Network Program

    Error:
    It gives me ArrayIndexOutOfBoundException
    at location Url url = new Url(args[0]);

    what should I do?

  4. #4
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    Default Re: Network Program

    I think you are not providing "Run Time Arguement" that's why it gives ArrayIndexOutOfBoundException.

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